Tom and Jerry went to a restaurant for dinner. Tom ordered 2 hamburgers and 1 soft drinks, totalling Rs.70. Jerry ordered 1 hamburgers and 2 soft drinks, totalling Rs.50.

Then the cost of one hamburger and one soft drink are

To solve this, we can set up two equations using the information provided. Let $H$ be the price of a hamburger and $S$ be the price of a soft drink.1. Create the Equations:Tom's Order: $2H + 1S = 70$ --- (Equation 1)Jerry's Order: $1H + 2S = 50$ --- (Equation 2)2. Use the Substitution or Elimination Method:Let’s use the Elimination Method. To eliminate $S$, we can multiply Equation 1 by $2$:$2 \times (2H + 1S = 70) \Rightarrow 4H + 2S = 140$ --- (Equation 3)Now, subtract Jerry's order (Equation 2) from Equation 3:$(4H + 2S) - (1H + 2S) = 140 - 50$$3H = 90$$H = 30$ (The cost of one hamburger)3. Find the price of the Soft Drink ($S$):Plug the value of $H$ back into Equation 2:$1(30) + 2S = 50$$30 + 2S = 50$$2S = 50 - 30$$2S = 20$$S = 10$ (The cost of one soft drink)VerificationTom: $2 \times (30) + 1 \times (10) = 60 + 10 = 70$ (Correct)Jerry: $1 \times (30) + 2 \times (10) = 30 + 20 = 50$ (Correct)