Maths question from Panchayat Secretary (VLW) exam, 2025 by JKSSB
Twice the number of marbles and thrice the number of coins with Raghav are 70. If Raghav has at least one marble and at least one coin, then which of these could be the number of coins that Raghav has?
Last updated May 30, 2026
Correct Answer:
Option D —
15
To find the possible number of coins Raghav has, we can set up a simple word problem based on the information provided.
Twice the number of marbles plus three times the number of coins equals seventy.
We are also told that Raghav has at least one marble and at least one coin. Because you cannot have a fraction of a marble or a coin, both amounts must be whole numbers.
The Step-by-Step Logic
If we want to find out how many marbles Raghav has based on his coins, we subtract three times the number of coins from seventy, and then divide that remainder by two.
For the number of marbles to come out as a clean whole number, the amount we divide by two must be an even number.
Seventy is already an even number.
Subtracting an odd number from an even number results in an odd number (which cannot be cleanly divided by two).
Therefore, three times the number of coins must result in an even number.
For three times the number of coins to be even, the number of coins itself must be an even number.
Testing the Options
Let's look at the choices provided:
(A) Eleven — Odd
(B) Twelve — Even
(C) Thirteen — Odd
(D) Fifteen — Odd
Since twelve is the only even option, let's double-check it:
If Raghav has twelve coins, three times that amount is thirty-six.
Subtracting thirty-six from seventy leaves us with thirty-four.
Dividing thirty-four by two gives us seventeen marbles.
Since seventeen is a valid whole number, this works out perfectly.
Conclusion
The correct option is (B) 12.
Answer verified by Quintessence Classes faculty — Karan Nagar, Srinagar.
