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Reasoning question from Jr. Assistant exam, 2026 by JKSSB

C, E, K, Q, W, ?

Last updated Sep 22, 2026
Correct Answer: Option A — C
Let us look at the numerical positions of these letters in the English alphabet:

C is the 3rd letter

E is the 5th letter

K is the 11th letter

Q is the 17th letter

W is the 23rd letter

Finding the Pattern

If we look at the gaps between the letters starting from E, there is a consistent jump of 6 letters each time:

E (5) plus 6 is 11 (K)

K (11) plus 6 is 17 (Q)

Q (17) plus 6 is 23 (W)

Finding the Next Letter

To find the next letter, we continue the pattern of adding 6:

W (23) plus 6 is 29.

Since there are only 26 letters in the alphabet, we wrap around to the beginning by subtracting 26.

29 minus 26 is 3.

The 3rd letter of the alphabet is C.
Answer verified by Quintessence Classes faculty — Karan Nagar, Srinagar.

About this question

JKSSB Jr. Assistant 2026

Details

Exam JKSSB
Recruitment Jr. Assistant
Year 2026
Subject Reasoning
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