Maths question from Jr. Assistant exam, 2026 by JKSSB
If a number 45678x9231 is divisible by 3, then how many values are possible for x ?
Last updated May 13, 2026
Correct Answer:
Option D —
4
The Calculation
Add the known digits together:
The number is 45678x9231.
Adding 4 plus 5 plus 6 plus 7 plus 8 plus 9 plus 2 plus 3 plus 1 gives a total of 45.
Determine the required value for x:
Since the current sum is 45, and 45 is already divisible by 3, the value of x must also be a digit that is divisible by 3 to keep the total sum a multiple of 3.
List the possible digits for x:
The digit x can be any single number from 0 to 9. The digits in that range that are divisible by 3 (including zero, since 45 plus 0 remains 45) are:
0 (45 plus 0 is 45)
3 (45 plus 3 is 48)
6 (45 plus 6 is 51)
9 (45 plus 9 is 54)
Conclusion
There are 4 possible values for x. Therefore, the correct option is D.
Answer verified by Quintessence Classes faculty — Karan Nagar, Srinagar.
