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Maths question from Naib Tehsildar exam, 2018 by JKSSB

The perimeter of a triangle is 24 cm and inradius of the triangle is 3.5 cm, then the area of the triangle is

Last updated Jun 24, 2026
Correct Answer: Option C — 42 sq. cm
Step-by-Step Calculation:
1. Find the semi-perimeter (s):The perimeter of the triangle is given as 24{ cm}. The semi-perimeter is half of the perimeter
s = {Perimeter}\{2} = {24}\{2} = 12{ cm}

2. Calculate the Area (A):Using the inradius (r = 3.5{ cm}) and the semi-perimeter (s = 12cm)
A = 3.5{ cm} times 12cm
A = 42{ sq. cm}

Final Result:
The area of the triangle is 42sq.cm
Answer verified by Quintessence Classes faculty — Karan Nagar, Srinagar.
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JKSSB Naib Tehsildar 2018

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Exam JKSSB
Recruitment Naib Tehsildar
Year 2018
Subject Maths
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