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JKSSB Social Forest Worker 2026 Previous Year Questions

Practice authentic exam questions with answers and explanations

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2026
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General Science 4 questions

2026 Prelims General Science
In the context of a concave mirror, if an object is placed at the focus, then- 

I. The image will be formed at infinity. 
II. The size of the image formed will be highly enlarged. 
III. The nature of the image will be virtual and erect. 

 Which of the above statements stands true?
A I only
B I and II only
C II and III only
D I,II and III
Correct Answer: Option B
The correct option is B) I and II only.

Explanation
When an object is placed at the principal focus (F) of a concave mirror:

Statement I is TRUE: The reflected rays become parallel to each other and meet at infinity.

Statement II is TRUE: The size of the image formed at infinity is highly enlarged (magnified).

Statement III is FALSE: The nature of the image is real and inverted, not virtual and erect. (A concave mirror forms a virtual and erect image only when the object is placed between the Pole and the Focus).
2026 Prelims General Science
Consider the following statements. 

I. Generally, metal oxides are acidic in nature. 
II. Generally, non-metal oxides are basic in nature. 

Which of the above statements are INCORRECT?  
A I only
B II only
C Both I and II
D Neither I Nor II
Correct Answer: Option C
Explanation
Both statements are INCORRECT because their chemical properties are reversed:

Statement I is incorrect: Metal oxides are generally basic in nature. When they react with water, they form bases (for example, sodium oxide reacts with water to form sodium hydroxide).

Statement II is incorrect: Non-metal oxides are generally acidic in nature. When they react with water, they form acids (for example, carbon dioxide reacts with water to form carbonic acid).
2026 Prelims General Science
What are the by-products of anaerobic respiration? 

I. Alcohol 
II. Carbon dioxide 
III. Water 
IV. Energy 
V. Lactic Acid 

 Choose the correct option: 
A All of the above
B I,III,IV and V only
C I,II and V only
D I,II,IV and V only
Correct Answer: Option D
Explanation
Anaerobic respiration occurs in the absence of oxygen and produces different end products depending on the organism:

Alcoholic Fermentation (in yeast and plants): Glucose breaks down into alcohol, carbon dioxide, and energy.

Lactic Acid Fermentation (in animal muscle cells and certain bacteria): Glucose breaks down into lactic acid and energy.

Why Water is excluded:
Water is only formed as a by-product during aerobic respiration, which requires oxygen. It is not produced during anaerobic respiration
2026 Prelims General Science
Which of the following are bacterial diseases? 

I. Tuberculosis 
II. Cholera 
III. Hepatitis 
IV. Leprosy 
V. Measles 
VI. Yellow Fever 
 
Choose the correct option:  
A I, II and V only
B I, II and IV only
C I, II, IV and VI only
D I, II, IV, V and VI only
Correct Answer: Option B
Correct Answer: B) I, II and IV only
Explanation:
Bacterial Diseases (I, II, IV):

I. Tuberculosis: Caused by the bacterium Mycobacterium tuberculosis.

II. Cholera: Caused by the bacterium Vibrio cholerae.

IV. Leprosy: Caused by the bacterium Mycobacterium leprae.

Viral Diseases (III, V, VI):

III. Hepatitis: Caused by various Hepatitis viruses (e.g., HAV, HBV, HCV).

V. Measles: Caused by the Measles virus (morbillivirus).

VI. Yellow Fever: Caused by the Yellow Fever virus (flavivirus).

Geography 7 questions

2026 Prelims Geography
Which of the following National Parks encompasses the catchment area of Kiber, Nanth, and Kiyar Nallas, all of which drain south-west into the Marwah river, locally called Mariv Sudir? 
A Dachigam National Park
B Kishtwar National Park
C Kazinag National Park
D Salim Ali National Park
Correct Answer: Option B
Kishtwar High Altitude National Park (located in the Kishtwar district of Jammu and Kashmir) encompasses the catchment area of the Kiber, Nanth, Kiyar, and Renai Nallas. These streams flow southwest into the Marwah River (locally known as Mariv Sudir or Marusudar), which eventually meets the Chenab River at Bhandarkoot near Kishtwar town.
2026 Prelims Geography
Which tributary of the river Jhelum originates from Lolab Valley in north south direction and joins the waters of the outfall channel of river Jhelum about 6.5 Km. downstream of Sopore town.  
A Doodhganga
B Pohru
C Lidder
D Rambiara
Correct Answer: Option B
The correct option is B) Pohru.

Explanation
Pohru River: Originates from the hills surrounding the Lolab Valley in Kupwara district. It flows in a north-to-south direction and joins the outfall channel of the Jhelum River near Doabgah, about 6.5 km downstream of Sopore.

Other Options:

Doodhganga: Originates from the Pir Panjal range and flows through Budgam and Srinagar.

Lidder: Originates from the Kolahoi Glacier in Anantnag district.

Rambiara: Originates in the Pir Panjal range and flows through Shopian district.
2026 Prelims Geography
Arrange the following processes in a correct sequence. 

I. Scouring 
II. Sorting 
III. Shearing 
IV. Rolling 
V. Cleaning 

Choose the correct option:  
A I-III-II-IV-V
B I-III-II-V-IV
C III-I-II-V-IV
D III-I-II-IV-V
Correct Answer: Option C
Step-by-Step Sequence for Wool Processing
III. Shearing: The fleece (wool coat) of the sheep is shaved off along with a thin layer of skin.

I. Scouring: The sheared fleece is thoroughly washed in tanks to remove grease, dust, and dirt.

II. Sorting: The washed hair is separated into different qualities based on texture.

V. Cleaning (of Burrs): Small fluffy fibers known as burrs are picked out from the hair.

IV. Rolling: The cleaned fibers are straightened, combed, and rolled into yarn.
2026 Prelims Geography
Which of the following pairs are correctly matched? 

I. Bagh-e-Bahu 
II. Nagin Lake 
III. Sasher Kangri 

Tawi River 
Jhelum River 
Nubra River 

Choose the correct match:  
A I only
B I and III only
C I and II only
D I, II and III
Correct Answer: Option D
Explanation of the Matches
I. Bagh-e-Bahu – Tawi River: Bagh-e-Bahu is located on the banks of the Tawi River in Jammu.

II. Nagin Lake – Jhelum River: Nagin (Nigeen) Lake in Srinagar is connected to the Jhelum River basin.

III. Sasher Kangri – Nubra River: Saser (Sasher) Kangri is a high mountain peak in the Karakoram range whose glaciers feed the tributaries of the Nubra River.
2026 Prelims Geography
If a group of tourists moves from Jammu to Srinagar by road, then most likely they will cross which mountain pass? 
A Fotu La
B Bara Lacha La
C Rohtang Pass
D Banihal Pass
Correct Answer: Option D
Explanation:
Banihal Pass: Situated in the Pir Panjal Range, it connects the Jammu region with the Kashmir Valley (Jammu to Srinagar via NH 44). The famous Jawahar Tunnel and the Banihal Qazigund Road Tunnel are built under this pass to ensure all-weather connectivity.

Other Options:
A) Fotu La: Located on the Srinagar-Leh highway in the Zaskar Range (Ladakh).

B) Bara Lacha La: Connects Lahaul district in Himachal Pradesh to Leh in Ladakh.

C) Rohtang Pass: Connects the Kullu Valley with the Lahaul and Spiti Valleys in Himachal Pradesh.
2026 Prelims Geography
Match the following. 

Glaciers 
i. Kangto Glacier 
ii. Rimo Glacier 
iii. Zemu Glacier 
iv. Bara Shigri 

States/UT 
a. Ladakh 
b. Arunachal Pradesh 
c. Sikkim 
d. Himachal Pradesh 

 Choose the correct match: 
A i-a, ii-b, iii-c, iv-d
B i-b, ii-c, iii-d, iv-a
C i-b, ii-a, iii-c, iv-d
D i-a, ii-c, iii-b, iv-d
Correct Answer: Option C
Correct Pairs:
i. Kangto Glacier → b. Arunachal Pradesh: Located in the Eastern Himalayas on the border of Arunachal Pradesh.

ii. Rimo Glacier → a. Ladakh: Located in the Karakoram Range within Ladakh.

iii. Zemu Glacier → c. Sikkim: The largest glacier in the Eastern Himalayas, located at the base of Mount Kangchenjunga in Sikkim.

iv. Bara Shigri → d. Himachal Pradesh: Located in the Lahaul and Spiti district of Himachal Pradesh, it is the largest glacier in the state.
2026 Prelims Geography
Consider the following statements about Laterite soils.

I. These are formed in areas with high temperatures and low rainfall. 
II. These soils contain excess iron oxide, giving them a reddish colour. 
III. Lime and silica get leached due to atmospheric conditions. 

Which of the above statements are INCORRECT?  
A I and II only
B I only
C II only
D None of the above
Correct Answer: Option B
Explanation:
Statement I is INCORRECT:
Laterite soils develop in tropical and subtropical regions characterized by high temperatures and heavy/high rainfall (with alternating wet and dry periods), not low rainfall.

Statement II is CORRECT:
Heavy rain washes away organic matter and soluble minerals, leaving behind oxides of iron and aluminium, which give laterite soil its distinct red color.

Statement III is CORRECT:
Due to intense tropical rains and intense leaching (desilication), lime and silica are leached away from the topsoil.

Polity 2 questions

2026 Prelims Polity
Chronologically arrange the following states based on the elevation to the status of a state under the Constitution of India. 
I. Himachal Pradesh 
II. Nagaland 
III. Arunachal Pradesh 
 IV. Statehood to Sikkim  
A I-II-IV-III
B II-I-III-IV
C II-I-IV-III
D I-II-III-IV
Correct Answer: Option C
Chronological Order of Statehood:
II. Nagaland (1963): Became the 16th state of India on December 1, 1963, by the State of Nagaland Act, 1962.

I. Himachal Pradesh (1971): Elevated from a Union Territory to the 18th state of India on January 25, 1971, under the State of Himachal Pradesh Act, 1970.

IV. Sikkim (1975): Became the 22nd state of India on May 16, 1975, via the 36th Constitutional Amendment Act, 1975.

III. Arunachal Pradesh (1987): Elevated from a Union Territory to the 24th state of India on February 20, 1987, under the State of Arunachal Pradesh Act, 1986.
2026 Prelims Polity
Which of the following pairs are correctly matched?
  
Description 
 Capitals 
 I. Judicial Capital of Arunachal Pradesh Itanagar 
 II. Judicial Capital of Goa 
Panaji 
III. Judicial Capital of Madhya Pradesh 
Jabalpur 

 Choose the correct match: 
A I only
B I and II only
C III only
D I and III only
Correct Answer: Option C
Explanation:
I. Judicial Capital of Arunachal Pradesh (Incorrect):
Arunachal Pradesh does not have its own principal High Court seat. It comes under the jurisdiction of the Guwahati High Court (located in Guwahati, Assam), though it has a permanent bench in Naharlagun (Itanagar).

II. Judicial Capital of Goa (Incorrect):
Goa falls under the jurisdiction of the Bombay High Court (located in Mumbai, Maharashtra), though a bench of the High Court operates in Panaji.

III. Judicial Capital of Madhya Pradesh (Correct):
While Bhopal is the executive/administrative capital of Madhya Pradesh, the principal seat of the High Court of Madhya Pradesh is located in Jabalpur, making it the state's judicial capital.

History 6 questions

2026 Prelims History
Identify the correct sequential order of the followinG dynasties.

I. Lohara Dynasty 
II. Utpal Dynasty 
III. Chak Dynasty 
IV. Shah Mir Dynasty 
A I-III-IV-II
B I-II-III-IV
C II-I-III-IV
D II-I-IV-III
Correct Answer: Option D
Chronological Order & Ruling PeriodsII.  Utpala Dynasty (c. 855 – 1003 CE) Founded by Avantivarman in 855 CE, this medieval Hindu dynasty succeeded the Karkota dynasty and brought significant agricultural and cultural developments to Kashmir. I. Lohara Dynasty (1003 – 1171 CE) Established by Sangramaraja in 1003 CE following the death of his aunt, Queen Didda. This was the last major Hindu dynasty covered in Kalhana's Rajatarangini. IV. Shah Mir Dynasty (1339 – 1561 CE) Founded by Shams-ud-din Shah Mir in 1339 CE, marking the establishment of Muslim sultanate rule in Kashmir. Notable rulers included Sultan Sikandar and Sultan Zain-ul-Abidin ("Budshah"). III. Chak Dynasty (1561 – 1586 CE) Founded by Ghazi Shah Chak in 1561 CE after overthrowing the weak Shah Mir rulers. They ruled until Kashmir was annexed into the Mughal Empire by Akbar in 1586 CE.  
2026 Prelims History
Consider the following pairs: 

I. Achabal Garden 
 a.Anantnag District
 
II. Avantipur Ruins 
b.Poonch District
 
III. Parihaspore archaeological sites 
c. Pulwamaa District 

Which of the above pairs are correctly matched?  
A I only
B I and II only
C II and III only
D All of the above
Correct Answer: Option A
Detailed Breakdown of the Pairs
Pair I is CORRECT:

Achabal Garden → Anantnag District

It is a famous Mughal garden built by Empress Nur Jahan around 1620 CE, located in the Anantnag district.

Pair II is INCORRECT:

Avantipur Ruins → Pulwama District (not Poonch District)

The ancient temple ruins of Awantiswami and Avantishwar, built by King Avantivarman in the 9th century, are located in Awantipora in the Pulwama district.

Pair III is INCORRECT:

Parihaspore Archaeological Sites → Baramulla District (not Pulwama District)

Parihaspore, the ancient capital city built by King Lalitaditya Muktapida of the Karkota dynasty in the 8th century, is located in the Baramulla district (Pattan area).
2026 Prelims History
'The Tripartite struggle' for control over the city of Kannauj was fought between which dynasties? 
A Palas, Senas, Pushyabhutis
B Palas, Pratiharas, Chalukyas
C Palas, Pratiharas, Reddis
D Palas, Pratiharas, Rashtrakutas
Correct Answer: Option D
Detailed Explanation
The Tripartite Struggle took place during the 8th to 10th centuries CE for control over Kannauj, which was considered the political symbol of imperial sovereignty in Northern India after the reign of Emperor Harsha.

The three major powers involved were:

The Palas of Eastern India (Bengal/Bihar region)

The Gurjara-Pratiharas of Western India (Rajasthan/Gujarat region)

The Rashtrakutas of Southern India (Deccan region)

The struggle lasted for over two centuries, ultimately weakening all three dynasties, though the Gurjara-Pratiharas eventually managed to maintain control over Kannauj for a longer period.
2026 Prelims History
Arrange the following events in a correct chronological order. 

I. Poorna Swaraj Resolution 
 II. Launch of Civil Disobedience Movement 
III. Poona Pact 
 IV. Second Round Table Conference
A I-II-III-IV
B I-II-IV-III
C II-I-IV-III
D II-I-III-IV
Correct Answer: Option B
Chronological Order & Key Dates
I. Poorna Swaraj Resolution (December 1929):

Passed during the Lahore Session of the Indian National Congress under the presidency of Jawaharlal Nehru, declaring complete independence as the ultimate goal.

II. Launch of Civil Disobedience Movement (March–April 1930):

Initiated by Mahatma Gandhi with the famous Dandi March (Salt March) starting on March 12, 1930, and officially breaking the salt law on April 6, 1930.

IV. Second Round Table Conference (September–December 1931):

Held in London, attended by Mahatma Gandhi as the sole representative of the Indian National Congress following the Gandhi-Irwin Pact.

III. Poona Pact (September 1932):

An agreement signed between Dr. B.R. Ambedkar and Mahatma Gandhi (in Yerwada Central Jail, Pune) regarding electoral representation for the depressed classes.
2026 Prelims History
Consider the following pairs: 
I. Silappadikaram 
1. Ilango Adigal

II. Manimegalai Sittalai 
2. Sattanar 

III. Buddhacharita 3.Ashvaghosha 

Which of the above pairs are correctly matched? 
A I only
B I and II only
C II and III only
D I, II and III
Correct Answer: Option D
Detailed Explanation
Pair I is CORRECT:

Silappadikaram (The Tale of an Anklet) is one of the Five Great Epics of Tamil literature, composed by the Jain monk Ilango Adigal around the 2nd to 5th century CE.

Pair II is CORRECT:

Manimegalai is a Tamil Buddhist epic written by the merchant-poet Sittalai Sattanar (also spelled Chithalai Chathanar). It serves as a sequel to Silappadikaram.

Pair III is CORRECT:

Buddhacharita (Acts of the Buddha) is a celebrated Sanskrit epic poem detailing the life of Gautama Buddha, composed by the philosopher and playwright Ashvaghosha during the 2nd century CE (Kushan period).
2026 Prelims History
Given below are two statements:

I. Bhakti saint Shankaradeva addressed "Vaishnav Dharma" as "Sanatan Dharma". 
II. Shankaradeva's main composition is Kirtanghosh.

Identify the correct statements- 
A I only
B II only
C Both I and II
D Neither I Nor II
Correct Answer: Option C
Detailed Explanation Statement I is CORRECT: Srimanta Sankardeva, the great 15th–16th century saint, social reformer, and scholar from Assam, referred to the faith he preached as "Sanatan Dharma" or "Bhagavati Dharma" (also popularly known as Ekasarana Dharma or Mahapurushiya Dharma). He viewed his devotional movement as a return to the original, eternal truth (Sanatan) centered on exclusive devotion (bhakti) to Krishna/Narayana.  
Statement II is CORRECT:The Kirtan Ghosha (or Kirtanghosh) is universally recognized as the magnum opus and primary devotional scripture composed by Srimanta Sankardeva. It contains a collection of narrative poetry meant for community chanting (Nama-Kirtana) and remains central to the Neo-Vaishnavite tradition in Assam.  

Current Affairs 4 questions

2026 Prelims Current Affairs
Jammu and Kashmir clinched their maiden Ranji Trophy title by defeating which opposition team? 
A Maharashtra
B Saurashtra
C Haryana
D Karnataka
Correct Answer: Option D
Key Highlights of the Win
Historic Victory: Jammu and Kashmir created history by winning their maiden Ranji Trophy title in the 2025–26 season by taking a 291-run first-innings lead against eight-time champions Karnataka at the KSCA Rajnagar Stadium in Hubballi.

Key Performers:

Shubham Pundir scored a crucial 121 in the first innings, earning Player of the Match honors.

Auqib Nabi took 5/54 in Karnataka's first innings and was named Player of the Tournament for his phenomenal season.

Qamran Iqbal (160*) and Sahil Lotra (101*) sealed the triumph on the final day.
2026 Prelims Current Affairs
Match the following: 

Sports Awards 
Awarded For 

 i. Major Dhyan Chand Khel Ratna Award 
a and Presented for good performance contributing towards the promotion of sports. 

 ii. Arjuna Award Lifetime 
 b. Given out for consistent good performance over a period of four years. 

 iii. Maulana Abul Kalam Azad Trophy 
 c. Awarded for outstanding performances in sports spanning over a period of four years. 

iv. Arjuna Award 
d. Given to the university for top performance in inter-university tournaments over the last one year. 

Choose the correct Match:  
A i-c, ii-a, iii-d, iv-b
B i-b, ii-d, iii-c, iv-a
C i-c, ii-d, iii-a, iv-b
D i-b, ii-a, iii-c, iv-d
Correct Answer: Option A
Detailed Mapping:
i. Major Dhyan Chand Khel Ratna Award → c.

Awarded for spectacular and most outstanding performance in the field of sports over a period of four years.

ii. Dronacharya Award (Lifetime) / Arjuna Award (Lifetime/Promotion) → a.

Presented for good performance contributing towards the promotion of sports over a long career. (Note: Option (a) refers to lifetime/promotional service).

iii. Maulana Abul Kalam Azad (MAKA) Trophy → d.

Given to the top-performing university in inter-university tournaments over the last year.

iv. Arjuna Award → b.

Given for consistent good performance, leadership, and discipline over a period of four years.

2. Ranji Trophy Question
Answer:

Jammu and Kashmir clinched their maiden Ranji Trophy title by defeating Karnataka.  
newsonair.gov.in

3. Exam Subject Categorization (JKSSB Syllabus)
Under the syllabus prescribed by the Jammu and Kashmir Services Selection Board (JKSSB)—such as for Panchayat Secretary (VLW), Naib Tehsildar, Sub-Inspector (JKP), or Accounts Assistant exams—these questions fall under the following syllabus sections:

Question 1 (Sports Awards):

Subject Section: General Knowledge & Current Affairs → National Sports Awards & Honours

Question 2 (J&K Ranji Trophy Victory):

Subject Section: General Knowledge with Special Reference to J&K UT → J&K Current Affairs & Achievements in Sports
2026 Prelims Current Affairs
Consider the following statements about the mission POEM conducted by ISRO.

I.  PS4-Orbital Experiment Module, designated as POEM, refers to the usage of the spent fourth stage of the Polar Satellite Launch Vehicle (PSLV). 

II. PSLV-C60 SpaDeX mission is the first POEM Mission of the upcoming series. 

Which of the above statements are correct?  
A I only
B II only
C Both I and II
D Neither I Nor II
Correct Answer: Option A
Detailed Explanation

Statement I is CORRECT:POEM stands for PSLV Orbital Experimental Module. It is an innovative initiative by ISRO that repurposes the spent fourth stage ($\text{PS4}$) of the Polar Satellite Launch Vehicle (PSLV)—which typically becomes space debris—into a stabilized orbital platform to host scientific payloads and perform microgravity experiments. 
Statement II is INCORRECT: The PSLV-C60 / SpaDeX mission carries POEM-4, making it the fourth mission in the POEM series. The very first POEM mission (POEM-1) was launched much earlier aboard the PSLV-C53 mission in June 2022.
2026 Prelims Current Affairs
Which of the following statements about the Research Development and Innovation Fund, approved by the Union Cabinet, is/are correct? 

I. The RDI Scheme incentivises private sector participation in R&D, with a total outlay of Rs. 10 Lakh crore over six years. 

II. It aims to finance transformative projects at higher levels of Technology Readiness Level (TRL) of 4 and above. 

Which of the statement are correct. 
A I only
B II only
C Both I and II
D Neither I Nor II
Correct Answer: Option B
Detailed Analysis of the Statements: 
Statement I is INCORRECT: While the scheme does incentivize private sector participation in R&D, the total outlay is ₹1 Lakh crore over six years (not ₹10 Lakh crore). Statement II is CORRECT: The primary objective of the scheme is to finance transformative projects at higher levels of technological maturity, specifically targeting Technology Readiness Level (TRL) 4 and above to help move concepts from the lab to commercialization.

English 28 questions

2026 Prelims English
You can take ___ of the two roads; both lead to the same village. 
A either
B neither
C every
D any
Correct Answer: Option A
The correct answer is A) either

Explanation:
Either: Refers to one or the other of two options. Since there are two roads and both reach the village, taking either choice works.

Why the other options are incorrect:
B) Neither: Means "not one nor the other" (not option A and not option B), which contradicts the statement that both roads lead to the village.

C) Every: Used for a group of three or more items.

D) Any: Typically used when choosing from a group of three or more choices (though occasionally used for two, "either" is the grammatically precise choice for choosing between strictly two alternatives).
2026 Prelims English
I have ___ friends who live in___ Netherlands, but I haven't visited them in years. 
A a few/no article
B few/the
C a few/the
D little/the
Correct Answer: Option C
Explanation:
First Blank (a few):

Friends is a plural countable noun, so we use few or a few (not little).

A few means "some" or "a small number" with a positive/neutral sense (i.e., "I have some friends").

Few (without "a") implies a negative meaning ("hardly any").

Second Blank (the):

The Netherlands is one of the country names that requires the definite article "the" because it is a plural noun structure.

Completed Sentence:
"I have a few friends who live in the Netherlands, but I haven't visited them in years."
2026 Prelims English
Fill in the blanks 
____ idea was it to leave the gate open all night?
A Who's
B Whose
C Whom
D Which
Correct Answer: Option B
The correct answer is B) Whose

Explanation:
Whose is a possessive pronoun used to ask or show who owns or is responsible for something (e.g., "Whose idea," "Whose coat").

Why the other options are incorrect:
A) Who's: A contraction for "Who is" or "Who has" ("Who's going to the store?"). Substituting it here gives "Who is idea was it...", which is grammatically incorrect.

C) Whom: Used as an objective pronoun (the object of a verb or preposition), e.g., "To whom did you give the keys?"

D) Which: Used to choose among a specific, limited set of items ("Which option do you prefer?").
2026 Prelims English
Which of the following sentences is structurally balanced and correct?
A The candidate was praised for her intelligence, dedication, and how well she communicates.
B The candidate was praised for her intelligence, dedication, and communication skills.
C The candidate was praised for being intelligent, dedication, and hard work.
D The candidate was praised for intelligence, dedicated, and working hard
Correct Answer: Option B
The correct answer is B) The candidate was praised for her intelligence, dedication, and communication skills.

Explanation:
This sentence uses parallel structure (or parallelism), which means using the same pattern of words to show that two or more ideas have the same level of importance.

In option B, all three listed items following the preposition "for her" are nouns / noun phrases:

intelligence (noun)

dedication (noun)

communication skills (noun phrase)

Why the other options are incorrect:
A) Mixes nouns with a dependent clause ("how well she communicates").

C) Mixes a gerund phrase ("being intelligent") with nouns ("dedication," "hard work").

D) Mixes a noun ("intelligence"), an adjective ("dedicated"), and a gerund phrase ("working hard").
2026 Prelims English
In the sentence "The book that I bought yesterday is missing," the underlined part is a/an: 
A Noun Clause
B Adjective Clause
C Adverbial Clause
D Main Clause
Correct Answer: Option B
Explanation:

Adjective Clause: "that I bought yesterday" describes or modifies the noun "book" by providing more details about which specific book is missing. Adjective clauses usually begin with relative pronouns like that, which, who, whom, or whose.

Why the other options are incorrect:
A) Noun Clause: Functions as a noun in the sentence (e.g., subject or object), which is not the case here.

C) Adverbial Clause: Modifies a verb, adjective, or adverb to show time, cause, condition, etc. (e.g., "when I got home").

D) Main Clause: The main independent clause in this sentence is "The book is missing".
2026 Prelims English
Convert the following Simple sentence into a Complex sentence without changing the meaning: 

 "Working hard, he passed the exam." 
A He worked hard and passed the exam.
B Because he worked hard, he passed the exam.
C He worked hard; therefore, he passed the exam.
D He passed the exam with hard work.
Correct Answer: Option B
Sentence Breakdown:
B) Complex sentence: Contains an independent clause ("he passed the exam") and a dependent/subordinate clause starting with a subordinating conjunction ("Because he worked hard").

Why the other options are incorrect:
A) Compound sentence: Joins two independent clauses with the coordinating conjunction and.

C) Compound sentence: Joins two independent clauses using a semicolon and the conjunctive adverb therefore.

D) Simple sentence: Contains only one independent clause with a prepositional phrase ("with hard work").
2026 Prelims English
Which of the following is an example of an Imperative sentence? 
A How wonderful the weather is today!
B Did you finish the report on time?
C Please ensure all windows are locked before leaving
D The sun rises in the east.
Correct Answer: Option C
The correct answer is C) Please ensure all windows are locked before leaving.

Breakdown of Sentence Types:
C) Imperative: Expresses a request, command, or instruction (often directed at an implied "you").

A) Exclamatory: Expresses strong emotion or excitement ("How wonderful...").

B) Interrogative: Asks a direct question ("Did you finish...").

D) Declarative: Makes a statement or states a fact ("The sun rises...").
2026 Prelims English
While most of the team was exhausted, the captain remained resilient, pushing everyone to finish the final lap." 

Choose the ANTONYM for resilient in this context: 
A Friable
B Tough
C Pliant
D Buoyant
Correct Answer: Option C
Explanation
Resilient: Refers to being able to withstand or recover quickly from difficult conditions, fatigue, or pressure (showing strength, toughness, and determination).

Pliant: Means easily bent, flexible, or yielding easily to pressure or influence—making it the antonym in this context (giving in easily under strain).

Friable: Means easily crumbled or pulverized (typically used for physical materials like soil or rock, rather than a person's physical or mental stamina).

Tough and Buoyant: Both share similar or supportive meanings to resilient (tough meaning durable/strong; buoyant meaning cheerful/upbeat).
2026 Prelims English
Her laconic reply suggested that she was not interested in continuing the conversation."

Choose the ANTONYM for laconic in this context: 
A condensed
B garrulous
C succinct
D taciturn
Correct Answer: Option B
Explanation
Laconic means using very few words; brief and concise.

Garrulous is an direct antonym, meaning excessively talkative, wordy, or rambling.

Condensed, Succinct, and Taciturn are all synonyms or close in meaning to laconic (using few words or being brief).
2026 Prelims English
The CEO's mercurial temperament made it difficult for the staff to predict how he would react to the news." 

 Choose the SYNONYM for mercurial in this context: 
A steadfast
B dependable
C capricious
D lethargic
Correct Answer: Option C
Explanation:

Mercurial means subject to sudden, unpredictable changes in mood or mind (unpredictable, volatile).

Capricious is a direct synonym, meaning given to sudden and unaccountable changes of mood or behavior.

Steadfast and Dependable are antonyms (meaning firm, reliable, and unchanging).

Lethargic means sluggish and apathetic.
2026 Prelims English
Select the correct spelling for the word meaning "an expert judge in matters of taste": 
A Connosseur
B Connoiseur
C Conoisseur
D Connoisseur
Correct Answer: Option D
Explanation
Connoisseur comes from the French word connaisseur (derived from connaître, meaning "to know").

A helpful way to remember the spelling is that it features double 'n' and double 's', along with the -ois- vowel combination in the middle: Con-nois-seur.
2026 Prelims English
Which spelling is correct for the word meaning "a small, exclusive group of people"? 
A Clike
B Cleek
C Clique
D Cleaque
Correct Answer: Option C
Explanation: 
Clique (pronounced kleek) refers to a small, close-knit, and often exclusive group of people who share similar interests and tend not to allow others to join easily.

The word is borrowed from French, which accounts for its unique spelling ending in -que.
2026 Prelims English
Select the correct spelling for the word meaning 
"a person who organises and operates a business": 
A Entreprenure
B Entraprenuer
C Entrepreneur
D Entreperneur
Correct Answer: Option C
Explanation
Entrepreneur comes from the French verb entreprendre (meaning "to undertake").

A common trick to remember the spelling is the ending: -neur (similar to words like chauffeur or poseur), rather than -nure or -neer.
2026 Prelims English
Select the most appropriate option: 

"When Mrs. X was younger, she run five miles without stopping." 
A can
B might
C could
D should
Correct Answer: Option C
Explanation
Past Ability (could): "Could" is the past tense form of "can" and is used to express general ability in the past. Since the sentence refers to a time when Mrs. X was younger, "could" is required.

Present Ability (can): Expresses present ability, which contradicts the past timeframe ("was younger").

Possibility / Advice (might / should): "Might" indicates possibility and "should" indicates advice or duty, neither of which expresses ability.
2026 Prelims English
Identify the sentence where the verb "have" acts as a main verb rather than an auxiliary: 
A I have finished my lunch.
B They have been working all day.
C We have a meeting at ten.
D Have they seen the movie yet?
Correct Answer: Option C
Explanation
Main Verb (have in C): Here, "have" is the primary verb in the sentence, indicating possession or an scheduled event. It is not helping another verb.

Auxiliary (Helping) Verb (have in A, B, and D): In these choices, "have" is used alongside another main verb to form perfect tenses:

A: "have" + main verb finished (Present Perfect)

B: "have" + auxiliary "been" + main verb working (Present Perfect Continuous)

D: "have" + main verb seen (Present Perfect question)
2026 Prelims English
In the sentence, "Radha may visit the museum", the word 'may' is a- 
A Main verb
B Transitive verb
C Gerund
D Modal verb
Correct Answer: Option D
Explanation
Modal Verb (may): A modal auxiliary verb used to express possibility, permission, or ability. In this sentence, "may" indicates the possibility of Radha visiting the museum.

Main Verb (visit): The primary action in the sentence.

Transitive Verb: A verb that requires a direct object (here, "visit" is transitive, taking "the museum" as its object).

Gerund: A verb form ending in -ing that functions as a noun (e.g., "Visiting").
2026 Prelims English
While the professor was __ the middle __ a lecture, a student broke ___ with a question. 
A at, for, out
B in, of, in
C within, of, through
D during, of, up
Correct Answer: Option B
Explanation:
In the middle of: A standard idiomatic phrase meaning in the central part or during the course of an activity.

"While the professor was in the middle of a lecture..."

Broke in: The phrasal verb break in means to interrupt someone who is talking.

"...a student broke in with a question."
2026 Prelims English
I cannot provide you __ a loan, as I am already beset __ financial difficulties and am answerable ___ my creditors. 
A with, with, to
B for, by, for
C to, of, with
D against, from, about
Correct Answer: Option A
Explanation:
Each verb/adjective in this sentence pairs with a specific fixed preposition:

Provide + [someone] + WITH + [something]:

When the object receiving the item comes first (you), use with.

"I cannot provide you with a loan..."

Beset + WITH:

To be troubled or overwhelmed by problems/difficulties.

"...as I am already beset with financial difficulties..."

Answerable + TO + [someone]:

To be held accountable or responsible to a person or authority.

"...and am answerable to my creditors."
2026 Prelims English
The young man was absorbed __ his work and was oblivious __ the noise occurring __ him. 
A in, by, besides
B with, of, beside
C in, to, around
D for, about, towards
Correct Answer: Option C
Explanation:
Each adjective/verb combination requires a specific preposition:

Absorbed + in: To be deeply involved or engrossed in something.

"The young man was absorbed in his work..."

Oblivious + to: To be unaware of or paying no attention to something.

"...and was oblivious to the noise..."

Occurring + around: Happening in the area surrounding someone.

"...occurring around him."
2026 Prelims English
Fill in the blanks :

He was acquitted__ the murder charge, but he was later charged __ theft and sentenced __ three years.
A from, for, with
B off, of, for
C of, with, to
D with, about, in
Correct Answer: Option B
Explanation:
Each verb requires a specific preposition:

Acquitted + of: You are acquitted of a crime/charge (cleared of charges).

"He was acquitted of the murder charge..."

Charged + with: You are charged with an offense (officially accused).

"...he was later charged with theft..."

Sentenced + to: You are sentenced to a specific punishment or length of time.

"...and sentenced to three years."
2026 Prelims English
Select the most appropriate antonym of the word IMPULSIVE
A Impetuous
B Whimsical
C Reflective
D Unpremedicated
Correct Answer: Option C
Explanation:
Impulsive means acting or done quickly without thought or planning (rash, hasty).

Reflective means thoughtful, deliberate, and given to deep contemplation before taking action—making it the exact antonym.

Meaning of other options:
Impetuous: Acting quickly and without care (synonym).

Whimsical: Subject to erratic, sudden, or unpredictable impulses (synonym/related).

Unpremedicated: Not treated with medication (unrelated, though "unpremeditated" would also be a synonym of impulsive).
2026 Prelims English
Select the most appropriate antonym of the word TACITURN
A Prolix
B Breviloquent
C Traumatise
D Reticent
Correct Answer: Option A
The correct option is A) Prolix.

Explanation:
Taciturn means naturally reserved, quiet, or saying very little.

Prolix means using far too many words, overly wordy, or tedious in speech—making it the exact antonym.

Meaning of other options:
Breviloquent: Speaking briefly or concisely (synonym/similar in meaning to taciturn).

Traumatise: To cause lasting emotional shock or upset (unrelated).

Reticent: Uninclined to speak or share thoughts freely (synonym of taciturn).
2026 Prelims English
Select the most appropriate synonym of the word CHASTE 
A Immaculate
B Wanton
C Ornate
D Debauched
Correct Answer: Option A
Explanation:
Chaste means pure, modest, virtuous, or uncorrupted by sin or fault.

Immaculate means perfectly clean, spotless, or pure, making it the closest synonym in meaning.

Meaning of other options:
Wanton: Sexually unrestrained, immoral, or reckless (antonym).

Ornate: Highly decorated or elaborate (opposite of chaste when describing design or style).

Debauched: Indulging in excessive sensual pleasures or corruption (antonym).
2026 Prelims English
Select the most appropriate synonym of the word SAGACIOUS
A Silly
B Stupid
C Sincere
D Wise
Correct Answer: Option D
Explanation:
Sagacious means having or showing keen mental discernment, good judgment, and wisdom (e.g., "a sagacious leader").

Wise is its direct synonym.

Meaning of other options:
Silly / Stupid: Antonyms of sagacious (foolish or lacking intelligence).

Sincere: Means genuine or honest, which is unrelated to wisdom.
2026 Prelims English
Identify the correct use of articles with plural nouns: 

I. Lions are fierce animals. 
II. Lions of Gir forest are famous worldwide. 
III. The lions we saw at the zoo were sleeping. 

 Choose the correct option: 
A Only II
B Only I and III
C Only II and III
D All are correct
Correct Answer: Option B
Explanation:
Sentence I is Correct:

"Lions are fierce animals."

Plural countable nouns used in a general sense do not take the definite article "the".

Sentence II is Incorrect:

"Lions of Gir forest are famous worldwide."

When a plural noun is modified or made specific by a phrase (here, "of Gir forest"), it must take the article "the".

Correct form: "The lions of Gir forest are famous worldwide."

Sentence III is Correct:

"The lions we saw at the zoo were sleeping."

"The" is correctly used because it refers to a specific group of lions (the particular ones seen at the zoo).
2026 Prelims English
Identify the correct sentence(s) regarding the use of article "The": 

I. The higher you climb, the colder it gets. 
II. He is the most hardworking of the two brothers. 
III. The gold is a precious metal.

Choose the correct option: 
A Only I
B I and II
C I and III
D All are correct
Correct Answer: Option A
Explanation:
Sentence I is Correct:

"The higher you climb, the colder it gets."

Uses the parallel comparison structure "The + comparative ..., the + comparative ...", which correctly requires the definite article before both comparative adjectives.

Sentence II is Incorrect:

"He is the most hardworking of the two brothers."

When comparing exactly two people or things, you must use the comparative degree rather than the superlative.

Correct form: "He is the more hardworking of the two brothers."

Sentence III is Incorrect:

"The gold is a precious metal."

Uncountable material nouns used in a general sense do not take the definite article "the".

Correct form: "Gold is a precious metal." (You only use "the gold" when referring to a specific batch of gold, e.g., "The gold in that vault").
2026 Prelims English
___  juice in this jug is bitter, but ___ juice is generally good for health. 
A No article, no article
B The, the
C The, no article
D No article, the
Correct Answer: Option C
"The juice in this jug is bitter, but juice is generally good for health."

Reason:
First blank ("The"): Uses the definite article "the" because it refers to a specific, particular quantity of juice (the specific juice inside this jug).

Second blank ("no article"): No article is used because "juice" is an uncountable noun being spoken about in a broad, general sense.
2026 Prelims English
Fill in the blanks :

____ rich should help ____ poor
A A, a
B The, a
C No article, the
D The, the
Correct Answer: Option D
Reason:
When the definite article "the" is placed before an adjective like rich or poor, it transforms the adjective into a plural noun representing the entire group of people (e.g., the rich means rich people, and the poor means poor people).

Reasoning 26 questions

2026 Prelims Reasoning
CUBE: 36:: CUBOID:? 
A 74
B 36
C 48
D 24
Correct Answer: Option B
To find the missing term, look at the geometric properties shared by both shapes:

A cube has 6 faces. Multiplying the number of faces by itself (6 multiplied by 6) gives 36.

A cuboid also has 6 faces. Multiplying the number of faces by itself (6 multiplied by 6) gives 36.

Therefore, the correct choice is B) 36.
2026 Prelims Reasoning
17: 136: 27: ?
A 223
B 269
C 243
D 257
Correct Answer: Option C
To find the missing term, look at how the first pair of numbers is related:

Look at the number 17:

The sum of its digits is 1 plus 7, which equals 8

17 multiplied by 8 gives 136

Apply the same rule to the number 27:

The sum of its digits is 2 plus 7, which equals 9

27 multiplied by 9 gives 243

Therefore, the correct choice is C) 243.
2026 Prelims Reasoning
In a certain code language, 'CANDLE' is written as 13451214. How will 'LIGHT' be written in the same language? 
A 8792012
B 7891220
C 9812720
D 1297820
Correct Answer: Option B
To find how LIGHT is written, look at the position of each letter in the alphabet and arrange them in ascending numerical order:

First, look at CANDLE:

C is the 3rd letter

A is the 1st letter

N is the 14th letter

D is the 4th letter

L is the 12th letter

E is the 5th letter

Arranging these alphabetical position numbers from smallest to largest gives: 1, 3, 4, 5, 12, 14.
Joining them together creates 13451214.

Now, apply the same steps to LIGHT:

L is the 12th letter

I is the 9th letter

G is the 7th letter

H is the 8th letter

T is the 20th letter

Arranging these position numbers from smallest to largest gives: 7, 8, 9, 12, 20.
Joining them together creates 7891220.

Therefore, the correct choice is B) 7891220.
2026 Prelims Reasoning
If 'BEAR' is written as 'AFBQ' and 'LION' is written as 'KJPM'. How will 'KITE' be written?
A JJUD
B LJUF
C FJSS
D LUFJ
Correct Answer: Option A
To find how KITE is written, look at the letter-by-letter pattern:

First example (BEAR to AFBQ):

B becomes A (one letter backward)

E becomes F (one letter forward)

A becomes B (one letter forward)

R becomes Q (one letter backward)

Second example (LION to KJPM):

L becomes K (one letter backward)

I becomes J (one letter forward)

O becomes P (one letter forward)

N becomes M (one letter backward)

Applying this same pattern to KITE:

K goes one letter backward to J

I goes one letter forward to J

T goes one letter forward to U

E goes one letter backward to D

Therefore, KITE becomes JJUD.

The correct choice is A) JJUD.
2026 Prelims Reasoning
Find the next term in the given series :
8, 7, 12, 33, 128_? 
A 512
B 384
C 540
D 635
Correct Answer: Option D
o find the next term, look at the pattern connecting each number:

Start with 8: 8 multiplied by 1, minus 1, gives 7

From 7 to 12: 7 multiplied by 2, minus 2, gives 12

From 12 to 33: 12 multiplied by 3, minus 3, gives 33

From 33 to 128: 33 multiplied by 4, minus 4, gives 128

Notice that at each step, both the multiplier and the number subtracted increase by 1.

To find the missing term:

Take 128, multiply by 5, and subtract 5

128 multiplied by 5 is 640

640 minus 5 gives 635

Therefore, the correct choice is D) 635.
2026 Prelims Reasoning
Which of the following options replaces the '?' in the given series 22, 23, 27, 36, ?, 77 
A 47
B 52
C 45
D 54
Correct Answer: Option B
To find the missing number, look at how much the series increases with each step.

From 22 to 23, the number increases by 1 (1 multiplied by 1)

From 23 to 27, the number increases by 4 (2 multiplied by 2)

From 27 to 36, the number increases by 9 (3 multiplied by 3)

The amount being added follows the sequence of square numbers.

Following this pattern, the next step needs to add 16 (4 multiplied by 4). Adding 16 to 36 gives 52.

To verify, the final step from 52 to 77 adds 25 (5 multiplied by 5), which matches the series.

Therefore, the correct choice is B) 52.
2026 Prelims Reasoning
Find the next term in the given series

12, 6, 6, 9, 18,? 
A 54
B 36
C 27
D 45
Correct Answer: Option D
Step-by-Step Breakdown
The series follows a pattern where each number is multiplied by an increasing factor that goes up by 0.5 at each step:

First transition: 12 multiplied by 0.5 equals 6

Second transition: 6 multiplied by 1.0 equals 6

Third transition: 6 multiplied by 1.5 equals 9

Fourth transition: 9 multiplied by 2.0 equals 18

Fifth transition: 18 multiplied by 2.5 equals 45
2026 Prelims Reasoning
Which of the following terms replaces the '?' in the given series 121, 130, 148, ?, 256 
A 184
B 166
C 196
D 175
Correct Answer: Option A
Step-by-Step Breakdown
First transition: The difference between 121 and 130 is 9.

Second transition: The difference between 130 and 148 is 18 (which is double the previous difference of 9).

Third transition: Doubling the difference again gives 36. Adding 36 to 148 gives 184.

Fourth transition: Doubling the difference once more gives 72. Adding 72 to 184 gives 256, which confirms the pattern is correct.
2026 Prelims Reasoning
In a research facility, there are 122 scientists. Some specialize in Quantum Physics (Q), Molecular Biology (M), and Organic Chemistry (O), while a few have no specialization in any of these fields. There are 65 in Q, 45 in M, and 42 in O. The intersection of Q and M is 20, Q and O is 25, and M and O is 15. The number of scientists in all three fields is exactly half the number of scientists who have no specialization in any of these three fields. How many scientists are specialized only in Organic Chemistry? 


A 10
B 12
C 15
D 18
Correct Answer: Option B
Here is the complete solution for the 122 scientists problem explained without using any math symbols:

Step-by-Step Breakdown
1. Understand the Overlaps
Total scientists in the facility: 122

Scientists in Quantum Physics: 65

Scientists in Molecular Biology: 45

Scientists in Organic Chemistry: 42

Scientists in both Quantum Physics and Molecular Biology: 20

Scientists in both Quantum Physics and Organic Chemistry: 25

Scientists in both Molecular Biology and Organic Chemistry: 15

2. Find the Number of Scientists in All Three Fields
Adding the three individual groups together gives sixty-five plus forty-five plus forty-two, which equals 152.

Adding the three two-field overlaps together gives twenty plus twenty-five plus fifteen, which equals 60.

Subtracting the two-field overlaps from the individual total gives one hundred fifty-two minus sixty, which equals 92.

This value of ninety-two accounts for everyone in at least one field, except that the group in all three fields has been removed one extra time. Therefore, the total number of scientists in at least one field is ninety-two plus the number of scientists in all three fields.

Since the total number of scientists (122) is equal to those in at least one field plus those in no field:

One hundred twenty-two equals ninety-two plus the number in all three fields plus the number in no field.

The problem states that the number in no field is double the number in all three fields.

Combining these means ninety-two plus three times the number in all three fields equals one hundred twenty-two.

Subtracting ninety-two from one hundred twenty-two leaves 30.

Dividing thirty by three gives 10.

So, exactly 10 scientists specialize in all three fields.

3. Calculate Scientists Specialized ONLY in Organic Chemistry
To find those specialized solely in Organic Chemistry:

Start with the total in Organic Chemistry: 42.

Subtract those who also do Quantum Physics: forty-two minus twenty-five leaves 17.

Subtract those who also do Molecular Biology: seventeen minus fifteen leaves 2.

Add back the scientists who do all three fields (since they were subtracted twice): two plus ten equals 12.

The correct option is B) 12.
2026 Prelims Reasoning
A circle is divided into 5 equal slices. In each figure, x slices are removed, and the remaining slices form a pattern that corresponds to a number. Observe the following: 

 Figure 1:When 2 slices are removed, the remaining pattern corresponds to 211. Figure 2: When I slice is removed, the remaining pattern corresponds to 1023.

When 0 slices are removed, what number will the remaining figure represent? 
A 3125
B 7776
C 6561
D 2401
Correct Answer: Option A
The pattern is formed by taking the number of remaining slices raised to the fifth power (the total number of slices) and subtracting the number of removed slices raised to the fifth power.

Figure 1 (2 slices removed, 3 remaining):
Three to the power of five is two hundred forty-three. Two to the power of five is thirty-two. Two hundred forty-three minus thirty-two gives 211.

Figure 2 (1 slice removed, 4 remaining):
Four to the power of five is one thousand twenty-four. One to the power of five is one. One thousand twenty-four minus one gives 1023.

Target Figure (0 slices removed, 5 remaining):
Five to the power of five is three thousand one hundred twenty-five. Zero to the power of five is zero. Three thousand one hundred twenty-five minus zero gives 3125.
2026 Prelims Reasoning
Rehman travelled 32km north, 17km south and then 8km east. How far is he away from his starting point and in which direction?  
A 13km, North
B 17km, North-East
C 13km, North-East
D 17km, East
Correct Answer: Option B
The correct option is B) 17km, North-East.

Step-by-Step Breakdown
Calculate Net North or South Movement:

Travels 32 km North

Travels 17 km South

Subtracting 17 from 32 gives 15 km North

Calculate Net East or West Movement:

Travels 8 km East

Find the Shortest Distance:

The square of 15 is 225

The square of 8 is 64

Adding 225 and 64 gives 289

The square root of 289 gives 17 km

Determine the Direction:

Since he is 15 km North and 8 km East from where he started, he is in the North-East direction.
2026 Prelims Reasoning
A man walks 57 m, turns right and walks 76 m, then turns right again and walks 57 m. If at the time of sunset, his shadow is to his left, in which direction did he start? 
A South
B East
C West
D North
Correct Answer: Option A
The correct option is A) South.

Step-by-Step Breakdown
Determine Final Facing Direction:

At sunset, the sun is in the West, so all shadows fall towards the East.

His shadow is to his left, which means his left side is pointing East.

If facing East is to his left, he must be facing North at the end of his walk.

Trace the Movements Backwards:

Final Direction: Facing North after making two right turns.

Two right turns equal a 180-degree change in direction (facing the exact opposite way from where he started).

Since he ended up facing North, he must have started walking facing South.

Verification
Start: Walk 57 m South.

Turn Right: Walk 76 m West.

Turn Right: Walk 57 m North.

Final state: Facing North at sunset, with East (and his shadow) to his left.
2026 Prelims Reasoning
At 9:15 am, the minute hand of a clock faces west. Then, at 6 pm on the same day, in which direction will the hour hand point? 
A South
B West
C East
D North
Correct Answer: Option D
Step-by-Step Breakdown
Analyze the Clock's Orientation:

At 9:15 am, the minute hand points at the 3 o'clock position.

Normally, on a standard compass/clock, 3 o'clock points East.

The question states that 3 o'clock faces West (rotated 180 degrees from standard).

Determine the Directions for the Clock Positions:

3 o'clock = West (Opposite of East)

9 o'clock = East (Opposite of West)

12 o'clock = South (Opposite of North)

6 o'clock = North (Opposite of South)

Find the Hour Hand Direction at 6:00 pm:

At 6:00 pm, the hour hand points directly at the 6 o'clock position.

Based on the rotated directions above, the 6 o'clock position points North.
2026 Prelims Reasoning
A man is facing north. He turns 135 degrees in the anti-clockwise direction. Then he turned 180 degrees in a clockwise direction. In which direction is he facing now?  
A North-west
B South-east
C North-east
D South-west
Correct Answer: Option C
Step-by-Step Breakdown
Initial Direction: Facing North

First Turn (135 degrees anti-clockwise):
Turning 135 degrees anti-clockwise from North puts him facing South-west.

Second Turn (180 degrees clockwise):
Turning 180 degrees from South-west puts him directly opposite, facing North-east.

Alternative Method (Net Calculation)
Clockwise movement: 180 degrees

Anti-clockwise movement: 135 degrees

Net turn: 180 minus 135 = 45 degrees clockwise

45 degrees clockwise from North is North-east.
2026 Prelims Reasoning
Find the odd number in the set 515, 732, 1725, 346 
A 515
B 732
C 1725
D 346
Correct Answer: Option C
The odd number in the set is C) 1725.

Pattern Explanation
All other numbers in the set follow the rule of a whole number cubed plus three:

346 is seven cubed (343) plus three.

515 is eight cubed (512) plus three.

732 is nine cubed (729) plus three.

1725 breaks this pattern because twelve cubed plus three is 1731 (or twelve cubed minus three is 1725).
2026 Prelims Reasoning
Which letter cluster is the odd one out? 
A KMI
B TVR
C FHE
D MOK
Correct Answer: Option C
Here is the pattern in simple terms

A KMI
K to M moves forward two letters
M to I moves back four letters

B TVR
T to V moves forward two letters
V to R moves back four letters

C FHE
F to H moves forward two letters
H to E moves back three letters

D MOK
M to O moves forward two letters
O to K moves back four letters

All other options move forward two positions and back four positions while FHE moves forward two positions and back three positions
2026 Prelims Reasoning
Which pair is the odd one out 
A 32-18
B 63-42
C 77-42
D 95-68
Correct Answer: Option D
Reason
Calculate the difference between the two numbers in each pair:

A) 32 - 18 = 14 (Multiple of 7)

B) 63 - 42 = 21 (Multiple of 7)

C) 77 - 42 = 35 (Multiple of 7)

D) 95 - 68 = 27 (Not a multiple of 7)

In pairs A, B, and C, the difference between the numbers is a multiple of 7, whereas in pair D, the difference is 27, which is not divisible by 7.
2026 Prelims Reasoning
Find the odd one out 
A Tsunami
B Cyclone
C Nuclear explosion
D Volcano
Correct Answer: Option C
Reason
Tsunami, Cyclone, and Volcano are all natural disasters caused by natural environmental and geological processes.

Nuclear explosion is a man-made disaster resulting from human activity.
2026 Prelims Reasoning
"My father is the only son of your Father", a man said to a woman. How is the woman related to the man?
A Sister-in-law
B Paternal aunt
C Mother
D Sister
Correct Answer: Option B
Step-by-Step Breakdown
"Your father": Refers to the woman's father.

"The only son of your father": Since the woman's father has only one son, that son must be the woman's brother.

"My father is...": Substituting the above into the statement gives: "My father is your brother."

Conclusion: Since the woman is the sister of the man's father, she is his paternal aunt.
2026 Prelims Reasoning
Arpan is the son of Barkha. Barkha has a sister Charu, who has a son Dharmesh and a daughter Aditi. Dharmesh has a paternal uncle Feroz. How is Arpan related to Dharmesh? 
A Father
B Son
C Uncle
D Cousin
Correct Answer: Option D
Step-by-Step Breakdown
Mother's Side: Barkha and Charu are sisters.

Arpan's Relation: Arpan is Barkha's son.

Dharmesh's Relation: Dharmesh is Charu's son.

Conclusion: Since Arpan and Dharmesh are the children of two sisters, they are cousins.

(Note: Feroz being Dharmesh's paternal uncle is extra information about Dharmesh's father's family and does not change the relation between Arpan and Dharmesh.)
2026 Prelims Reasoning
Introducing a woman, Rohan said, "Her mother is the only daughter of my mother-in-law". How is the woman related to Rohan?
A Wife
B Niece
C Daughter
D Mother
Correct Answer: Option C
Step-by-Step Breakdown
My mother-in-law: Refers to Rohan's mother-in-law.

The only daughter of my mother-in-law: Since Rohan's mother-in-law has only one daughter, that daughter must be Rohan's wife.

Her mother is...: Substituting the result above into the statement gives: "The woman's mother is Rohan's wife."

Conclusion: Since the woman's mother is Rohan's wife, the woman is Rohan's daughter.
2026 Prelims Reasoning
Pointing to a photograph, Anisha said, "I did not have any siblings, but that woman's father is the only son of my grandfather". Whose photograph was it? 
A Her mother
B Herself
C Her cousin
D Her daughter
Correct Answer: Option B
Step-by-Step Breakdown
The only son of my grandfather: Anisha's grandfather has only one son, which means that person must be Anisha's father.

That woman's father: Substituting the phrase above into the sentence gives us: "That woman's father is Anisha's father."

No siblings: Since Anisha stated that she has no brothers or sisters, the woman whose father is Anisha's father can only be Anisha herself.
2026 Prelims Reasoning
IfRAM-16 and DAM-9, then DREAMS=? 
A 36
B 30
C 28
D 32
Correct Answer: Option B
Pattern Explanation
The code value is calculated by adding up the alphabetical position of each letter in the word, then dividing that total by two.

Example 1: RAM
R is letter 18

A is letter 1

M is letter 13

Sum of positions: 18 plus 1 plus 13 gives 32

Calculation: 32 divided by 2 gives 16

Example 2: DAM
D is letter 4

A is letter 1

M is letter 13

Sum of positions: 4 plus 1 plus 13 gives 18

Calculation: 18 divided by 2 gives 9

Word: DREAMS
D is letter 4

R is letter 18

E is letter 5

A is letter 1

M is letter 13

S is letter 19

Sum of positions: 4 plus 18 plus 5 plus 1 plus 13 plus 19 gives 60

Calculation: 60 divided by 2 gives 30
2026 Prelims Reasoning
a certain language, 'CHANGE' is written as 'BDFHIO' and 'AMEND' is written as 'BEFNO'. How will 'SHIFT" be coded in that language? 
A GIJTU
B TFHIS
C TIJGU
D FHSIT
Correct Answer: Option A
The correct answer is A) GIJTU.

Pattern Explanation
Shift every letter of the word forward by one position in the alphabet.

Arrange the resulting letters in alphabetical order.

Example 1: CHANGE

C shifts to D

H shifts to I

A shifts to B

N shifts to O

G shifts to H

E shifts to F

Arranging D, I, B, O, H, F alphabetically gives BDFHIO.

Example 2: AMEND

A shifts to B

M shifts to N

E shifts to F

N shifts to O

D shifts to E

Arranging B, N, F, O, E alphabetically gives BEFNO.

Applying to SHIFT

S shifts to T

H shifts to I

I shifts to J

F shifts to G

T shifts to U

Arranging T, I, J, G, U alphabetically gives GIJTU.
2026 Prelims Reasoning
WOMEN: EOMNW:: APPLE: ? 
A EALSP
B AELPP
C LPPEA
D EALPP
Correct Answer: Option C
To find the pattern, look at the positions of the letters in the word WOMEN:

W (Position 1)

O (Position 2)

M (Position 3)

E (Position 4)

N (Position 5)

Reordering these letters to form EOMNW uses the position sequence: 4, 2, 3, 5, 1.

Now, apply the same positional sequence (4, 2, 3, 5, 1) to the word APPLE:

A (Position 1)

P (Position 2)

P (Position 3)

L (Position 4)

E (Position 5)

Position 4 = L

Position 2 = P

Position 3 = P

Position 5 = E

Position 1 = A

Putting them together gives LPPEA.
2026 Prelims Reasoning
HUMAN: NOSE:: FROGS: ?
A NOSE
B GILLS
C SKIN
D LUNGS
Correct Answer: Option B
This analogy compares the primary organ used for breathing/gas exchange:

Human : Nose — Humans primary entry point for drawing air into the respiratory system is through the nose.

Frogs : Skin — While adult frogs have basic lungs, they rely heavily on cutaneous respiration, absorbing oxygen and releasing carbon dioxide directly through their moist skin

Computer 1 questions

2026 Prelims Computer
In a software firm of 200 developers, everyone knows at least one language: Python (P), Java (J), and C++. The number of developers who know only Python is equal to the number of developers who know only Java. 30 developers know only C++. Exactly 10 developers know all three languages. 35 developers know both Python and Java, 25 know both Java and C++, and 30 know both Python and C++. What is the total number of developers who know Python? 
A 50
B 85
C 105
D 115
Correct Answer: Option C
Step -by-Step Breakdown
1. Break Down the Known Regions
Developers who know all three languages: 10

Developers who know both Python and Java: 35

Subtracting the ten who know all three leaves 25 who know only Python and Java.

Developers who know both Java and C++: 25

Subtracting the ten who know all three leaves 15 who know only Java and C++.

Developers who know both Python and C++: 30

Subtracting the ten who know all three leaves 20 who know only Python and C++.

Developers who know only C++: 30

2. Find the Number of Developers Who Know Only Python
Combining all known exclusive groups gives:

Thirty (only C++) plus twenty-five (only Python and Java) plus fifteen (only Java and C++) plus twenty (only Python and C++) plus ten (all three languages).

This totals 100 developers in these specific combined groups.

Since all two hundred developers know at least one language:

Subtracting one hundred from two hundred leaves 100 developers remaining.

These remaining one hundred developers are split equally between those who know only Python and those who know only Java.

Dividing one hundred by two gives 50 developers who know only Python (and 50 who know only Java).

3. Calculate Total Python Developers
To find the total number of developers who know Python, sum all groups that include Python:

Developers who know only Python: 50

Developers who know only Python and Java: 25

Developers who know only Python and C++: 20

Developers who know all three languages: 10

Fifty plus twenty-five plus twenty plus ten equals 105.

Maths 34 questions

2026 Prelims Maths
A library has 300 rare books categorised by Fiction (F), Hardcover (H), and Best-sellers (B). There are 140 Fiction books, 120 Hardcover books, and 100 Best-sellers. 40 books are both Fiction and Hardcover, 30 are both Hardcover and Best-sellers, and 50 are both Fiction and Best-sellers. Exactly 20 books follow in all three categories. How many books are either Fiction or Hardcover, but not both, and are not Best-sellers? 
A 110
B 120
C 140
D 160
Correct Answer: Option C
Step-by-Step Breakdown
1. Determine the Overlaps Between Categories
Items in all three categories: 20

Items in both First and Second categories: 40

Removing the twenty items that belong to all three categories leaves 20 items that belong to only the First and Second categories.

Items in both First and Third categories: 50

Removing the twenty items that belong to all three categories leaves 30 items that belong to only the First and Third categories.

Items in both Second and Third categories: 30

Removing the twenty items that belong to all three categories leaves 10 items that belong to only the Second and Third categories.

2. Find Items Belonging Exclusively to One Category
Only the First category:
Start with the total for the First category (140), then subtract those shared with only the Second category (20), those shared with only the Third category (30), and those shared across all three (20).

One hundred forty minus twenty, minus thirty, minus twenty leaves 70.

Only the Second category:
Start with the total for the Second category (120), then subtract those shared with only the First category (20), those shared with only the Third category (10), and those shared across all three (20).

One hundred twenty minus twenty, minus ten, minus twenty leaves 70.

3. Combine the Exclusive Groups
The target count consists of items belonging strictly to either the First category alone or the Second category alone:

Seventy plus seventy gives 140.
2026 Prelims Maths
A survey of 500 people was conducted regarding their ownership of Smartwatches (S), Tablets (T), and VR Headsets (V). 285 people own a Smartwatch, 215 own a Tablet, and 115 own a VR Headset. Exactly 45 people own all three devices. There are 70 who own a Smartwatch and a VR Headset, while 50 own a Tablet and a VR Headset. 50 people own none of these devices. How many people own a Smartwatch and a Tablet, but not a VR Headset? 
A 45
B 55
C 90
D 105
Correct Answer: Option A
Step-by-Step Breakdown
1. Determine the Group Sizes
Total people surveyed: 500

People owning no devices: 50

People owning at least one device: five hundred minus fifty, which equals 450

2. Break Down the VR Headset Group
Total VR Headset owners: 115

People owning all three devices: 45

People owning a Smartwatch and a VR Headset: 70

Removing the forty-five who own all three leaves 25 people who own a Smartwatch and a VR Headset, but not a Tablet.

People owning a Tablet and a VR Headset: 50

Removing the forty-five who own all three leaves 5 people who own a Tablet and a VR Headset, but not a Smartwatch.

Now subtract these sub-groups from the total VR Headset owners to find those who own only a VR Headset:

One hundred fifteen minus twenty-five minus five minus forty-five leaves 40 people owning only a VR Headset.

3. Find the Total Overlap Between Smartwatch and Tablet
Using the total numbers for each device:

Adding the total for Smartwatches (285), Tablets (215), and VR Headsets (115) gives 615.

Adding the known overlaps for Smartwatch with VR Headset (70) and Tablet with VR Headset (50) gives 120.

Subtracting this combined overlap of one hundred twenty from six hundred fifteen leaves 495.

Adding back the forty-five people who own all three devices gives 540.

Since four hundred fifty people own at least one device, the total number of people who own both a Smartwatch and a Tablet is the difference between five hundred forty and four hundred fifty, which equals 90.

4. Calculate Smartwatch and Tablet (No VR Headset)
Total owning both Smartwatch and Tablet: 90

Subtract the people who also own a VR Headset: 45

Ninety minus forty-five leaves 45 people.
2026 Prelims Maths
A right circular cylinder and a sphere have the same radius r. If their total surface areas are also exactly equal, what is the ratio of the volume of the cylinder to the volume of the sphere?
A 3:4
B 2:3
C 9:8
D 3:2
Correct Answer: Option A
Explanation
To find the ratio of their volumes, we first determine the height of the cylinder relative to its radius using their surface areas:

Equating Total Surface Areas:

The total surface area of a sphere is four multiplied by pi multiplied by the radius squared.

The total surface area of a cylinder is two multiplied by pi multiplied by the radius multiplied by the sum of its height and radius.

Setting these equal to each other and simplifying shows that the height of the cylinder must be equal to its radius.

Comparing Volumes:

The volume of the cylinder (with height equal to radius) is pi multiplied by the radius cubed.

The volume of the sphere is four-thirds multiplied by pi multiplied by the radius cubed.

Finding the Ratio:

Dividing the volume of the cylinder by the volume of the sphere gives one divided by four-thirds.

Simplifying this fraction yields three-fourths, which gives a volume ratio of 3:4.
2026 Prelims Maths
A wooden toy is shaped like a rocket with a cone mounted on a cylinder. The total height of the rocket is 26 cm, while the height of the conical part is 8 cm. The base of the conical portion has a diameter of 12 cm, while the base diameter of the cylindrical portion is 6 cm. The conical portion is to be painted orange and the cylindrical portion yellow. Calculate the total cost of painting the orange portion in terms of a, if the cost of painting is 0.1 Rs per mm².
A 870π
B 8700π
C 2025 π
D 202.5π
Correct Answer: Option A
The correct option is A) 870π.

Explanation
To find the total cost of painting the orange portion, we first find the total surface area of the cone exposed to be painted, convert it to square millimeters, and multiply by the unit cost:

Dimensions of the Cone:

Radius of the cone base is six centimeters (half of twelve centimeters).

Height of the cone is eight centimeters.

Using the Pythagorean relationship, the slant height is ten centimeters.

Surface Area of the Orange Region:

Curved surface area of the cone equals six multiplied by ten multiplied by pi, which is sixty pi square centimeters.

Base area of the cone equals six squared multiplied by pi, which is thirty-six pi square centimeters.

Base area of the attached cylinder equals three squared multiplied by pi, which is nine pi square centimeters.

The exposed base area around the cylinder is thirty-six pi minus nine pi, which equals twenty-seven pi square centimeters.

Total exposed orange surface area is sixty pi plus twenty-seven pi, which equals eighty-seven pi square centimeters.

Converting Units and Calculating Cost:

Since one square centimeter equals one hundred square millimeters, eighty-seven pi square centimeters equals eight thousand seven hundred pi square millimeters.

Multiplying eight thousand seven hundred pi square millimeters by zero point one Rupees per square millimeter gives a total cost of eight hundred seventy pi Rupees.
2026 Prelims Maths
A wooden toy is shaped like a rocket with a cone mounted on a cylinder. The total height of the rocket is 26 cm, while the height of the conical part is 8 cm. The base of the conical portion has a diameter of 12 cm, while the base diameter of the cylindrical portion is 6 cm. The conical portion is to be painted orange and the cylindrical portion yellow. Which of the following statements is correct regarding the orange-painted area? 
A The orange area is simply the Curved Surface Area (CSA) of the cone
B The orange area is the sum of the CSA of the cone and the area of the base of the cone
C The orange area is calculated as (CSA of cone) + (Base area of cone - Base area of cylinder)
D The orange area is calculated as (CSA of cone) + (CSA of cylinder)
Correct Answer: Option C
The correct statement is C) The orange area is calculated as (CSA of cone) + (Base area of cone - Base area of cylinder).

Explanation
To understand why option C is correct, consider which parts of the conical top are exposed to be painted orange:

Curved Surface Area (CSA) of the Cone: The entire slanted outer surface of the cone is exposed and must be painted orange.

Base of the Cone: Since the base of the cone (12 cm diameter) is wider than the top of the cylinder (6 cm diameter), the cylinder does not cover the entire bottom of the cone.

Overlapping Base Region: The base of the cylinder attaches to the center of the cone's base. The region where they overlap is hidden and attached to the cylinder, leaving a ring-shaped surface around the cylinder that is exposed on the underside of the cone.

Therefore, the total area to be painted orange equals the curved surface area of the cone plus the exposed ring at the bottom, which is calculated by subtracting the base area of the cylinder from the base area of the cone.
2026 Prelims Maths
A solid metallic sphere of radius R is melted and recast into n identical small solid spheres of radius r. Let S be the surface area of the original large sphere and s be the sum of the surface areas of all n small spheres. Identify the single correct relationship between s and S: 
A s = S
B s = n ^ (1/3) * S
C s = n ^ (2/3) * S
D s = nS
Correct Answer: Option B
To find the relationship between the surface area of the original sphere and the combined surface area of the smaller spheres, we look at volume conservation:

Volume Conservation:
The total volume remains unchanged during melting. The volume of the large sphere equals n times the volume of one small sphere. Since volume depends on the cube of the radius, the cube of the large radius R equals n multiplied by the cube of the small radius r. Taking the cube root, the large radius R equals the small radius r multiplied by n raised to the power of one-third. Therefore, the ratio of the large radius R to the small radius r is n raised to the power of one-third.

Surface Area Comparison:
Surface area depends on the square of the radius. The surface area S of the large sphere is proportional to the square of R. The surface area of a single small sphere is proportional to the square of r, so the sum of the surface areas s of all n small spheres is n multiplied by the square of r.

Ratio of Surface Areas:
Dividing the total small surface area s by the large surface area S gives n multiplied by the square of the ratio of r to R. Since R divided by r equals n raised to the power of one-third, r divided by R equals one divided by n raised to the power of one-third. Squaring this fraction gives one divided by n raised to the power of two-thirds.

Final Relation:
Multiplying n by one divided by n raised to the power of two-thirds simplifies to n raised to the power of one-third (since one minus two-thirds equals one-third).

Thus, the sum of the surface areas s equals n raised to the power of one-third multiplied by S.
2026 Prelims Maths
The LCM of two numbers is 180, and their HCF is 6. One of the numbers is 18 and the other number can be written in the form 6k What is the value of k? 
A k = 6
B k = 10
C k = 8
D k = 12
Correct Answer: Option C
To find the missing value, we use the property that the product of two numbers equals the product of their Highest Common Factor and Lowest Common Multiple.

Multiply the Highest Common Factor and the Lowest Common Multiple: six multiplied by one hundred eighty equals one thousand eighty.

The product of the two numbers must also equal one thousand eighty.

Divide one thousand eighty by the given number, eighteen, which gives sixty for the second number.

Since the second number is expressed as six times k, divide sixty by six to get ten.

Therefore, the value of k is ten.
2026 Prelims Maths
The LCM of two expressions is 3x ^ 3 + 18x ^ 2 + 30x + 12 and their HCF is x + 2 One of the expressions is x + 2 What is the sum of the coefficients (a,b), if the other expression can be represented as k(x ^ 2 + ax + b) ?  
A 3
B 4
C 5
D 6
Correct Answer: Option D
To find the other expression, divide the Lowest Common Multiple by the Highest Common Factor.

Dividing three x cubed plus eighteen x squared plus thirty x plus twelve by x plus two gives three x squared plus twelve x plus six.

Factoring out the constant three from this expression gives three times the quantity x squared plus four x plus two.

Comparing this to the form k times the quantity x squared plus a x plus b, we get:

The constant k equals three

The coefficient a equals four

The constant b equals two

The sum of the coefficients a and b is four plus two, which equals six.
2026 Prelims Maths
Identify the single correct statement regarding the properties of HCF and LCM:  
A If the product of two numbers is 2028 and their HCF is 13, there are exactly 2 such pairs of numbers possible
B The HCF of any two numbers always divides their LCM
C If the HCF of two numbers is 8, then 60 can never be their LCM
D All of the above statements are correct
Correct Answer: Option D
Statement A is correct:
If the Highest Common Factor is 13, the two numbers can be written as 13 multiplied by a and 13 multiplied by b, where a and b share no common factors. Multiplying these together gives 169 multiplied by a and b, which equals 2028. Dividing 2028 by 169 gives a multiplied by b equal to 12. The only pair of factors of 12 with no common factors are (1, 12) and (3, 4). This gives exactly two valid pairs of numbers: (13, 156) and (39, 52).

Statement B is correct:
It is a fundamental mathematical rule that the Highest Common Factor of any set of numbers always divides their Lowest Common Multiple completely without leaving a remainder.

Statement C is correct:
Since the Highest Common Factor must divide the Lowest Common Multiple, and 8 does not divide 60 evenly (60 divided by 8 leaves a remainder of 4), 60 can never be the Lowest Common Multiple for two numbers whose Highest Common Factor is 8.

Since statements A, B, and C are all true, Option D is the single correct answer.
2026 Prelims Maths
A florist is preparing for a large event and has 200 roses and 180 orchids. She wants to create the maximum possible number of identical bouquets such that every bouquet has the same number of roses and orchids, and no flowers are left over. How many roses will be present in each bouquet? 
A 10
B 20
C 9
D 18
Correct Answer: Option A
Step 1: Find the maximum number of bouquets
To make the maximum possible number of identical bouquets with no leftover flowers, we need to find the largest number that divides evenly into both two hundred and one hundred eighty.

The numbers that divide evenly into two hundred are one, two, four, five, eight, ten, twenty, twenty-five, forty, fifty, one hundred, and two hundred.

The numbers that divide evenly into one hundred eighty are one, two, three, four, five, six, nine, ten, twelve, fifteen, eighteen, twenty, thirty, forty-five, sixty, ninety, and one hundred eighty.

The largest number present in both lists is twenty.

Therefore, the florist can make a maximum of 20 identical bouquets.

Step 2: Calculate the number of roses per bouquet
The florist has two hundred roses in total.

Dividing two hundred roses equally among twenty bouquets gives 10 roses in each bouquet.

Correct Answer:
A) 10
2026 Prelims Maths
Two numbers are chosen at random from the set {1, 2, 3, 4, 5, 6) without replacement. What is the probability that their sum is prime? 
A 1/3
B 2/5
C 7/15
D 8/15
Correct Answer: Option C
Here is the step-by-step breakdown using plain text without any mathematical symbols:

Step 1: Find the total number of unique pairs
The set contains six numbers: one, two, three, four, five, and six.

Choosing any two numbers from these six gives a total of fifteen unique combinations:

Pairs starting with 1: (1, 2), (1, 3), (1, 4), (1, 5), (1, 6) — 5 pairs

Pairs starting with 2: (2, 3), (2, 4), (2, 5), (2, 6) — 4 pairs

Pairs starting with 3: (3, 4), (3, 5), (3, 6) — 3 pairs

Pairs starting with 4: (4, 5), (4, 6) — 2 pairs

Pairs starting with 5: (5, 6) — 1 pair

Step 2: Identify pairs with a prime sum
A prime number is a number greater than one that can only be divided by one and itself. The possible prime sums we can reach are three, five, seven, and eleven.

Pairs that sum to three: (1, 2) — 1 pair

Pairs that sum to five: (1, 4) and (2, 3) — 2 pairs

Pairs that sum to seven: (1, 6), (2, 5), and (3, 4) — 3 pairs

Pairs that sum to eleven: (5, 6) — 1 pair

Adding these together gives one plus two plus three plus one, which equals seven favorable pairs.

Step 3: Calculate the probability
Favorable outcomes: 7

Total possible pairs: 15

The probability of choosing two numbers whose sum is prime is 7 out of 15.

Correct Answer:
C) 7/15
2026 Prelims Maths
A bag contains 4 red, 3 blue, and 3 green balls. Three balls are drawn without replacement. What is the probability that exactly two balls are of the same colour and one is different? 
A 18/20
B 13/45
C 30/45
D 13/20
Correct Answer: Option D
Here is the step-by-step breakdown using plain text without any mathematical symbols:

Step 1: Find the total number of ways to pick three balls
The bag contains four red, three blue, and three green balls, making a total of ten balls.

The number of ways to select any three balls out of ten without regard to order is one hundred twenty ways.

Step 2: Calculate the favorable ways for each color pair
We need three balls where exactly two share one color and the third ball is a different color.

Case 1: Two Red balls and one non-Red ball

Choosing two red balls out of four gives six ways.

Choosing one non-red ball from the remaining six balls (three blue and three green) gives six choices.

Combining these yields six times six, which equals thirty-six ways.

Case 2: Two Blue balls and one non-Blue ball

Choosing two blue balls out of three gives three ways.

Choosing one non-blue ball from the remaining seven balls (four red and three green) gives seven choices.

Combining these yields three times seven, which equals twenty-one ways.

Case 3: Two Green balls and one non-Green ball

Choosing two green balls out of three gives three ways.

Choosing one non-green ball from the remaining seven balls (four red and three blue) gives seven choices.

Combining these yields three times seven, which equals twenty-one ways.

Step 3: Calculate the total favorable ways and probability
Adding all favorable outcomes together: thirty-six plus twenty-one plus twenty-one gives seventy-eight favorable ways.

The probability is therefore seventy-eight out of one hundred twenty.

Dividing both seventy-eight and one hundred twenty by six reduces the fraction to thirteen out of twenty.

Correct Answer:
D) 13/20
2026 Prelims Maths
A die is thrown 3 times. What is the probability that the sum is even, given that at least one 6 appears and all three outcomes are not the same?
A 1/2
B 3/5
C 4/7
D 5/9
Correct Answer: Option A
Here is the step-by-step breakdown using plain text without any mathematical symbols:

Step 1: Count the total valid outcomes (the given condition)
We are looking for outcomes where at least one 6 appears, but all three dice are not identical (which excludes the combination of three 6s).

Case 1: Exactly one 6 and two non-6s

The 6 can land on the first, second, or third die (3 possible positions).

The other two dice can be any number from 1 through 5 (5 choices each).

3 positions times 5 choices times 5 choices gives 75 outcomes.

Case 2: Exactly two 6s and one non-6

The non-6 can land on the first, second, or third die (3 possible positions).

The non-6 die can be any number from 1 through 5 (5 choices).

3 positions times 5 choices gives 15 outcomes.

Adding both cases together gives 90 total possible outcomes under the given condition.

Step 2: Count the outcomes where the sum is even
Since 6 is an even number, adding a 6 to a total does not change whether the total sum is even or odd.

For Case 1 (One 6 and two non-6s):

The sum will be even if the remaining two non-6 dice sum to an even number.

Two numbers sum to an even number if both are even or both are odd.

Both even (chosen from 2 or 4): 2 choices times 2 choices gives 4 ways.

Both odd (chosen from 1, 3, or 5): 3 choices times 3 choices gives 9 ways.

Total ways for the non-6 dice to sum to even: 4 plus 9 gives 13 ways.

Multiply by the 3 positions for the 6: 3 times 13 gives 39 favorable outcomes.

For Case 2 (Two 6s and one non-6):

Two 6s sum to twelve (an even number), so the remaining single non-6 die must be even.

The remaining die must be chosen from 2 or 4 (2 choices).

Multiply by the 3 positions for the non-6 die: 3 times 2 gives 6 favorable outcomes.

Adding the favorable outcomes from both cases gives 39 plus 6, which equals 45 favorable outcomes.

Step 3: Calculate the probability
Favorable outcomes: 45

Total given outcomes: 90

Probability: 45 out of 90, which simplifies to 1 out of 2 (one half).

Correct Answer:
A) 1/2
2026 Prelims Maths
A coin is tossed 5 times. Each head contributes +1 and each tail contributes-1. What is the probability that the total sum is exactly +1? 
A 5/16
B 5/32
C 10/16
D 2/3
Correct Answer: Option A
Here is the step-by-step breakdown without using any math symbols:

Step 1: Find the total number of outcomes
Each time a coin is tossed, there are two possible outcomes: heads or tails.

For five tosses, the total number of possible sequences is calculated by doubling the possibilities for each additional toss: two, four, eight, sixteen, thirty-two.

Thus, there are 32 total possible outcomes.

Step 2: Determine the required heads and tails
Each head adds one point, and each tail subtracts one point.

To reach a final score of positive one across five tosses, you must get three heads and two tails.

Three heads contribute three points, and two tails take away two points, leaving a final score of positive one.

Step 3: Count the successful combinations
There are 10 different ways to land three heads and two tails in five tosses:

Head, Head, Head, Tail, Tail

Head, Head, Tail, Head, Tail

Head, Head, Tail, Tail, Head

Head, Tail, Head, Head, Tail

Head, Tail, Head, Tail, Head

Head, Tail, Tail, Head, Head

Tail, Head, Head, Head, Tail

Tail, Head, Head, Tail, Head

Tail, Head, Tail, Head, Head

Tail, Tail, Head, Head, Head

Step 4: Calculate the probability
There are 10 favorable outcomes out of 32 total possibilities, making the probability 10 out of 32.

Reducing this fraction by halving both numbers gives 5 out of 16.

Correct Answer:
A) 5/16
2026 Prelims Maths
The present age of a man is equal to the square of his son's age. One year ago, the man's age was exactly eight times the age of his son. Two years hence, the sum of their ages will be 6 more than six times the son's age at that time. If the son's present age is 'x', which of the following represents the man's present age? 
A 25 years
B 36 years
C 49 years
D 64 years
Correct Answer: Option C
Step 1: Set up their present ages
The son's present age is given as x.

The man's present age is the square of the son's age, which means x times x.

Step 2: Use the condition from one year ago
One year ago, the son was x minus 1 years old.

One year ago, the man was x times x, minus 1 years old.

The problem states that one year ago, the man was eight times as old as his son:

Eight times the son's past age is eight times x, minus 8.

Setting this equal to the man's past age gives: x times x, minus 1 equals eight times x, minus 8.

Rearranging this gives: x times x, minus eight times x, plus 7 equals zero.

Finding the number that satisfies this relationship:

If x is 7, then 7 times 7 is 49.

49 minus 56 (which is eight times 7) plus 7 equals zero.

Therefore, the son's present age x is 7 years old.

Step 3: Calculate the man's present age
Since the son is 7 years old, the man's present age is 7 times 7, which equals 49 years old.

Step 4: Verify with the future condition
Two years from now, the son will be 9 years old (7 plus 2).

Two years from now, the man will be 51 years old (49 plus 2).

The sum of their future ages will be 60 (51 plus 9).

Six times the son's future age is 54 (six times 9).

Six more than 54 is indeed 60, which confirms the answer is correct.

Correct Answer:
C) 49 years
2026 Prelims Maths
An HR department is auditing the ages of its 5-member executive board A, B, C, D, and E, to comply with a "balanced experience" policy. The average age of the board members is 25 years. Member D (age 30) quits and is replaced by Member F. The new average age becomes 24 years. Additionally, Member B is 5 years younger than Member C. Member A is 2 years older than Member F. Member E and Member B have same age. What is the current age of Member E? 
A 20 years
B 21 years
C 25 years
D 27 years
Correct Answer: Option B
Step 1: Find Member F's age
For five members to average 25 years, their total age combined must be 125 years.

Since Member D is 30 years old, the remaining four members (A, B, C, and E) have a combined total age of 95 years (125 minus 30).

When Member F replaces Member D, the new average age for the five members becomes 24 years, making the new total age 120 years.

Since A, B, C, and E account for 95 years of that total, Member F must be 25 years old (120 minus 95).

Step 2: Find Member A's age
Member A is two years older than Member F.

Since Member F is 25 years old, Member A is 27 years old.

Step 3: Find Member E's age
Now we look at the new board total of 120 years for members A, B, C, E, and F:

Members A and F together contribute 52 years (27 plus 25).

Subtracting 52 from the overall total of 120 leaves 68 years split among members B, C, and E.

Member C is five years older than Member B. Taking away those extra 5 years leaves 63 years.

Member E and Member B are the same age, meaning B, E, and the base portion of C are three equal shares.

Dividing 63 years into three equal parts gives 21 years for each share.

Therefore, Member E is 21 years old.

Correct Answer:
B) 21 years
2026 Prelims Maths
Six years ago, the ratio of the ages of Kunal and Sagar was 6:5. Four years hence, the ratio of their ages will be 11:10. Based on this information, identify the single correct statement from the list below: 
A Sagar is currently 18 years old
B Sum of their current ages is 32 years
C Six years ago, Kunal was 12 years old
D 2 years ago, the ratio of their ages was 5:4
Correct Answer: Option C
Step 1: Set up their ages
Six years ago:

Kunal's age was 6 parts.

Sagar's age was 5 parts.

Present day (6 years later):

Kunal is 6 parts plus 6 years.

Sagar is 5 parts plus 6 years.

Four years from now:

Kunal will be 6 parts plus 10 years.

Sagar will be 5 parts plus 10 years.

Step 2: Find the value of 1 part
Four years from now, their ages will be in a 11 to 10 ratio.

10 times Kunal's future age equals 11 times Sagar's future age.

10 times (6 parts plus 10 years) gives 60 parts plus 100 years.

11 times (5 parts plus 10 years) gives 55 parts plus 110 years.

Comparing both sides:

60 parts plus 100 equals 55 parts plus 110.

The difference of 5 parts equals 10 years.

Divide 10 by 5 to find that 1 part equals 2 years.

Step 3: Calculate their current ages
Kunal's present age: 6 parts plus 6 years = 12 plus 6 = 18 years old.

Sagar's present age: 5 parts plus 6 years = 10 plus 6 = 16 years old.

Step 4: Check the options
A) Sagar is currently 18 years old — Incorrect (he is 16).

B) Sum of their current ages is 32 years — Incorrect (18 plus 16 is 34).

C) Six years ago, Kunal was 12 years old — Correct (18 minus 6 is 12).

D) Two years ago, the ratio of their ages was 5 to 4 — Incorrect (16 to 14 reduces to 8 to 7).

Correct Answer:
C) Six years ago, Kunal was 12 years old
2026 Prelims Maths
Match the scenarios in List-I with the correct "Present Age of the Older Person" in List-II.

List-I 
 P. The sum of the ages of a father and son is 45 years. Five years ago, the product of their ages was four times the father's age at that time. 
Q. A man is 24 years older than his son. In two years, his age will be twice the age of his son.
R. The ratio of the ages of A and B is 3:4. The sum of their ages is 28. 
S. 10 years ago, a father was 4 times as old as his son. 2 years hence, he will be twice as old as his son.  

List-II 
1) 16years
2) 36years 
3) 46years 
4) 34 years

Choose the correct match: 
A P-1, Q-2, R-3, S-4
B P-2, Q-1, R-3, S-4
C P-2, Q-3, R-1, S-4
D P-3, Q-2, R-4, S-1
Correct Answer: Option C
Here is the step-by-step breakdown without using math symbols:

1. Scenario P
The total sum of the father and son's present ages is 45 years.

Five years ago, the product of their ages was four times the father's age at that time.

This means the son's age five years ago was 4 years old.

Adding 5 years gives the son's present age as 9 years old.

Subtracting 9 from 45 gives the father's present age as 36 years (matches 2).

2. Scenario Q
A man is 24 years older than his son.

In two years, the difference in their ages remains 24 years, but the father will be twice as old as the son.

For the father to be twice as old with a difference of 24 years, the son must be 24 years old in two years, and the father must be 48 years old.

Subtracting 2 years gives the father's present age as 46 years (matches 3).

3. Scenario R
The ratio of the ages of A and B is 3 to 4, which totals 7 equal parts.

Dividing the total sum of 28 by 7 gives 4 years per part.

The older person has 4 parts, so multiplying 4 by 4 gives 16 years (matches 1).

4. Scenario S
Let the son's age ten years ago be 1 part, making the father's age 4 parts.

Twelve years later (two years from now), the father is twice as old as the son.

Working through the age gap reveals that ten years ago the son was 6 and the father was 24.

Adding 10 years gives the father's present age as 34 years (matches 4).

Conclusion
The correct matching sequence is P-2, Q-3, R-1, S-4.
2026 Prelims Maths
If x/ay/bz/ck, then find the value of: (bx + cy + az) / k
B abc
C a + b + c
D ab + bc + ac
Correct Answer: Option D
Here is the step-by-step breakdown without using math symbols:

1. Express x, y, and z in Terms of k
From the given equal ratios, x over a equals k, which means x equals a times k.

Similarly, y over b equals k, which means y equals b times k.

Likewise, z over c equals k, which means z equals c times k.

2. Substitute the Values into the Expression
The term b times x becomes b times a times k, or a times b times k.

The term c times y becomes c times b times k, or b times c times k.

The term a times z becomes a times c times k, or a times c times k.

Adding these three terms together gives k times the quantity a times b plus b times c plus a times c.

3. Divide by k
Dividing the combined total by k cancels out k.

This leaves a times b plus b times c plus a times c.

Conclusion
Correct Answer: D) ab + bc + ac
2026 Prelims Maths
A high-end jeweller manufactures gold bars where the price of a bar is directly proportional to the square of its weight. During transit, a bar of weight 5 units and worth Rs. 25,000 accidentally breaks into two pieces with weights in the ratio 2:3. What is the total reduction in the value of the gold due to this breakage? 
A Rs. 5,000
B Rs. 12,000
C Rs. 13,000
D Rs. 14,000
Correct Answer: Option B
Here is the step-by-step solution without using math symbols:

1. Determine the Value Per Weight Unit
The price of a gold bar is proportional to the square of its weight.

For the original bar of weight 5 units, the square of its weight is 25.

Given that 25 squared units of weight equal 25,000 rupees, each squared unit of weight is worth 1,000 rupees (25,000 divided by 25).

2. Calculate the Value of the Broken Pieces
The bar breaks into two pieces with weights of 2 units and 3 units.

For the first piece of weight 2 units:

Squaring the weight gives 4.

Multiplying 4 by 1,000 rupees per unit gives a value of 4,000 rupees.

For the second piece of weight 3 units:

Squaring the weight gives 9.

Multiplying 9 by 1,000 rupees per unit gives a value of 9,000 rupees.

The total value of both pieces combined is 13,000 rupees (4,000 plus 9,000).

3. Calculate the Reduction in Value
Subtracting the combined broken value of 13,000 rupees from the original value of 25,000 rupees gives a total loss of 12,000 rupees.

Conclusion
Correct Answer: B) Rs. 12,000
2026 Prelims Maths
If a:bc:d, which of the following is correct using Componendo and Dividendo? 
A (a + b) / (a - b) = (c + d) / (c - d)
B (a - b) / (a + b) = (c + d) / (c - d)
C (a + c) / (b + d) = (a - c) / (b - d)
D (a + b) / c = (b + d) / a
Correct Answer: Option A
1. Understand Componendo and Dividendo
If four quantities form a proportion such that a is to b as c is to d, then the ratio of the sum of the first two terms to their difference equals the ratio of the sum of the last two terms to their difference.

2. Apply the Rule
Take the left side: a plus b divided by a minus b.

Take the right side: c plus d divided by c minus d.

Equating both sides gives a plus b over a minus b equals c plus d over c minus d.

Conclusion
Correct Answer: A) (a + b) / (a - b) = (c + d) / (c - d)
2026 Prelims Maths
Match the mathematical descriptions (List-A) with their corresponding ratios (List-B):

List-A  
i. Sub-duplicate ratio of 25:36 
ii. Duplicate ratio of 3:4 
iii. Reciprocal ratio of 5:7 
iv. Compound ratio of 2:3 and 9:4  

List -B 
a. 9:16 
b. 3:2 
c. 5:6 
d. 7:5

 Choose the correct match:  
A i-d, ii-a, iii-b, iv-c
B i-b, ii-c, iii-a, iv-d
C i-c, ii-d, iii-a, iv-b
D i-c, ii-a, iii-d, iv-b
Correct Answer: Option D
1. Sub-duplicate ratio of 25 to 36
The sub-duplicate ratio means taking the square root of each number.

The square root of 25 is 5, and the square root of 36 is 6.

This gives the ratio 5 to 6 (matches c).

2. Duplicate ratio of 3 to 4
The duplicate ratio means squaring each number.

3 squared is 9, and 4 squared is 16.

This gives the ratio 9 to 16 (matches a).

3. Reciprocal ratio of 5 to 7
The reciprocal ratio means reversing the position of the terms.

Inverting 5 to 7 gives 7 to 5 (matches d).

4. Compound ratio of 2 to 3 and 9 to 4
The compound ratio is found by multiplying the first terms together and the second terms together.

Multiplying 2 by 9 gives 18, and multiplying 3 by 4 gives 12.

Reducing 18 to 12 gives 3 to 2 (matches b).

Conclusion
The correct matching sequence is i-c, ii-a, iii-d, iv-b.

Correct Answer: D) i-c, ii-a, iii-d, iv-b
2026 Prelims Maths
A train covers a distance S at a speed U. If its speed is increased by 10km / h the travel time reduces by 2 hours, and if increased by 20km / h the time reduces by 3 hours. Find the distance S. 
A 60 km
B 90 km
C 120 km
D 150 km
Correct Answer: Option C
1. Set up the Relationships
Let the original speed be U kilometers per hour and the original time be T hours.

The total distance S is calculated as speed multiplied by time.

For the first scenario, increasing the speed by 10 kilometers per hour decreases the travel time by 2 hours. Multiplying this new speed by the new time gives the distance S, which simplifies to: 10 times T minus 2 times U equals 20.

For the second scenario, increasing the speed by 20 kilometers per hour decreases the travel time by 3 hours. Multiplying this new speed by the new time gives the distance S, which simplifies to: 20 times T minus 3 times U equals 60.

2. Solve for Time and Speed
From the first scenario, expressing U in terms of T gives: U equals 5 times T minus 10.

Substituting this expression for U into the second scenario equation gives: 20 times T minus 3 times the quantity 5 times T minus 10 equals 60.

Expanding and combining like terms yields: 5 times T plus 30 equals 60, which means 5 times T equals 30.

Dividing 30 by 5 reveals the original time T is 6 hours.

Plugging 6 back into the speed formula gives U equals 5 times 6 minus 10, which means the original speed U is 20 kilometers per hour.

3. Calculate Distance S
The total distance S is the original speed multiplied by the original time.

Multiplying 20 kilometers per hour by 6 hours yields a total distance of 120 kilometers.

Conclusion
Correct Answer: C) 120 km
2026 Prelims Maths
The speed of a car travelling from city A to city B was recorded as 60km / h and the journey time was noted as 5 hours. However, the actual speed was 50 km/h. Calculate the real time taken for the trip.  
A 4.5 hours
B 6 hours
C 5.5 hours
D 5 hours
Correct Answer: Option B
1. Calculate the Total Distance
The recorded speed was 60 kilometers per hour.

The recorded journey time was 5 hours.

Multiplying the speed of 60 by the time of 5 gives a total distance of 300 kilometers.

2. Calculate the Real Time Taken
The actual speed was 50 kilometers per hour.

The distance to cover remains 300 kilometers.

Dividing the total distance of 300 by the real speed of 50 gives 6 hours.

Conclusion
The real time taken for the trip is 6 hours.
2026 Prelims Maths
A contractor assigns a task to two workers, A and B. Worker A can complete the work in x days, while worker B takes 5 days more than A. Working together, they can finish the task in 6 days. Find the value of x.
A 12
B 8
C 10
D 6
Correct Answer: Option C
1. Define Daily Work Rates
Worker A completes the task in x days, which means worker A completes 1 over x of the task per day.

Worker B takes 5 days longer, which is x plus 5 days, meaning worker B completes 1 over x plus 5 of the task per day.

Working together, they finish the task in 6 days, making their combined daily work rate 1 over 6.

2. Combine Rates and Simplify
Adding their individual daily rates together gives 1 over x plus 1 over x plus 5, which equals 1 over 6.

Combining the left side over a common denominator gives two x plus 5 over x squared plus 5 x, equal to 1 over 6.

Cross-multiplying to eliminate the fractions gives 6 times two x plus 5, which equals x squared plus 5 x.

Expanding the left side gives 12 x plus 30 equals x squared plus 5 x.

Moving all terms to one side gives the quadratic equation: x squared minus 7 x minus 30 equals 0.

3. Solve for x
Factoring this equation yields x minus 10 times x plus 3 equals 0.

This provides two possible values for x: 10 or negative 3.

Since time in days cannot be negative, x must be 10.

Conclusion
Correct Answer: C) 10
2026 Prelims Maths
A, B, and C can complete a complex engineering project in 25 days working together. The ratio of their individual efficiencies is 4:3: 5 respectively. The project begins with all three working together. However, the following events occur: After 5 days, A leaves the project. To compensate for A's departure, B increases his efficiency 33.3%, while C continues to work at his original efficiency. C leaves d days before the completion of project. The entire project is completed in exactly 35 days. What is the value of d? 
A 4
B 6
C 5
D 8
Correct Answer: Option C
1. Calculate the Total Work Required
The daily efficiencies of A, B, and C are 4, 3, and 5 units per day.

Working together, their combined daily output is 12 units (4 plus 3 plus 5).

Since they can complete the project in 25 days, the total project size is 300 units (12 units per day multiplied by 25 days).

2. Work Completed in the First 5 Days
For the first 5 days, all three work together at their combined rate of 12 units per day.

Work completed in these 5 days is 60 units (5 multiplied by 12).

Remaining work to finish is 240 units (300 minus 60).

Remaining time to finish the project is 30 days (35 total days minus the 5 days already spent).

3. Determine Output for the Remaining 30 Days
A leaves the project.

B increases efficiency by one-third (33.3 percent), raising B's daily output from 3 to 4 units.

C remains at an efficiency of 5 units per day.

B stays for the entire remaining 30 days, completing 120 units of work (30 days multiplied by 4 units per day).

4. Calculate Days Worked by C and the Value of d
The work left for C to complete during these 30 days is 120 units (240 remaining units minus B's 120 units).

Since C contributes 5 units per day, C needs 24 days to complete 120 units (120 divided by 5).

Since the second phase lasts 30 days and C only works for 24 days, C leaves 6 days before the project ends (30 minus 24).

Conclusion
The value of d is 6.
2026 Prelims Maths
The average score of a group of n students in a mathematics competition is 60. A series of adjustments is made to the data. The top 25% of students (by score) are removed from the data set. Their average score was 80. A new group of 10 students joins the remaining group. This new group has an average score of 40. After these changes, it was discovered that a score belonging to one of the original remaining students was misrecorded as 100 instead of 80. After all departures, additions, and corrections, the final average score of the group is exactly 50. What was the original number of students (n)? 
A 36
B 40
C 44
D 48
Correct Answer: Option D
Step-by-Step Breakdown
1. Initial State
Let the original number of students be n.

The original average score is 60.

The original combined score is 60 times n.

2. Removing the Top Quarter
The top 25 percent means one-fourth of the total students, or 0.25 times n.

Their average score was 80, making their combined score 80 times 0.25 times n, which equals 20 times n.

Removing these students leaves three-fourths of the students, or 0.75 times n.

The combined score of the remaining students is 60 times n minus 20 times n, which equals 40 times n.

3. Adding New Students and Correcting the Error
A new group of 10 students with an average score of 40 joins, adding 400 total marks (10 times 40).

The total number of students becomes 0.75 times n plus 10.

A misrecorded score of 100 instead of 80 is corrected, which reduces the total score by 20 marks.

The final total score is 40 times n plus 380 (400 minus 20).

4. Solving for the Original Number of Students
The final average score of 50 means the total score equals 50 times the new group size (0.75 times n plus 10).

Multiplying 50 by 0.75 times n plus 10 gives 37.5 times n plus 500.

Equating the two total scores: 40 times n plus 380 equals 37.5 times n plus 500.

Subtracting 37.5 times n from 40 times n leaves 2.5 times n.

Subtracting 380 from 500 leaves 120.

Therefore, 2.5 times n equals 120.

Dividing 120 by 2.5 yields 48 original students.
2026 Prelims Maths
The average score of 20 students in a class is 75. It is later found that 5 students had been absent. In a re-examination, 4 of them scored 85 each. After including the marks of all 5 students, the overall average becomes 77. Determine the marks scored by the fifth student. 
A 80
B 87
C 85
D 89
Correct Answer: Option B
Step-by-Step Breakdown
1. Calculate Initial Total Marks
The average score for the initial 20 students is 75.

Multiplying 20 students by 75 gives a total of 1,500 marks.

2. Calculate New Total Marks for All Students
Including the 5 absent students brings the total number of students to 25 (20 plus 5).

The new overall average for all 25 students is 77.

Multiplying 25 students by 77 gives a new total of 1,925 marks.

3. Find the Total Marks Scored by the 5 Students
Subtracting the initial 1,500 marks from the new total of 1,925 marks leaves 425 marks scored by the 5 additional students.

4. Calculate the Fifth Student's Score
4 of the students scored 85 marks each, which equals 340 marks in total (4 multiplied by 85).

Subtracting 340 marks from the 425 total marks scored by the group leaves 85 marks for the fifth student.
2026 Prelims Maths
The average of 12 students in a class is 68. Later, it was found that one student's score was incorrectly recorded as 72 instead of 96. What is the correct average of the class? 
A 70
B 71.33
C 72.5
D 73.4
Correct Answer: Option A
Step-by-Step Breakdown
1. Calculate the Difference in Score
The score was recorded as 72 instead of 96.

The actual score is higher by 24 marks (96 minus 72).

2. Distribute the Extra Marks
These extra 24 marks need to be shared equally among all 12 students.

Dividing 24 marks by 12 students increases each student's share by 2 marks.

3. Calculate the Correct Average
Adding the 2 additional marks to the original average of 68 gives the correct average of 70.
2026 Prelims Maths
The average score of 10 students in a class is 72. One student scored 90 marks, and another scored 30 marks less than the first. If these two students are removed, what is the new average of the remaining students? 
A 71.2
B 72.5
C 73.4
D 74.6
Correct Answer: Option A
Step-by-Step Breakdown
1. Calculate the Total Score of All Students
The average score of 10 students is 72.

Multiplying 10 students by 72 gives a total combined score of 720 marks.

2. Find the Scores of the Two Removed Students
The first student scored 90 marks.

The second student scored 30 marks less than the first student, which gives 60 marks (90 minus 30).

Combined, these two students scored 150 marks (90 plus 60).

3. Calculate the Total Score of Remaining Students
Removing 150 marks from the total of 720 marks leaves 570 marks (720 minus 150).

Removing two students leaves 8 students remaining (10 minus 2).

4. Calculate the New Average
Dividing the remaining total of 570 marks by 8 students gives a new average of 71.25 marks (approximately 71.2).
2026 Prelims Maths
A storekeeper gives 20% discount on an item and then adds 12% sales tax on the discounted price. If the original price of the item is Rs 500, which of the following statements is INCORRECT? 
A The discounted price is Rs. 400.
B The sales tax on the discounted price is Rs. 48.
C The final price the customer pays is Rs. 450.
D The final price is less than the original price.
Correct Answer: Option C
Step-by-Step Breakdown
1. Calculating the Discounted Price
The original price is Rupees 500.

A 20 percent discount on Rupees 500 equals Rupees 100.

Subtracting Rupees 100 from Rupees 500 leaves a discounted price of Rupees 400.

Statement A is correct.

2. Calculating the Sales Tax
A 12 percent sales tax is calculated on the discounted price of Rupees 400.

12 percent of Rupees 400 equals Rupees 48.

Statement B is correct.

3. Calculating the Final Price
Adding the tax of Rupees 48 to the discounted price of Rupees 400 gives a final price of Rupees 448.

Statement C claims the final price is Rupees 450, which is wrong.

Statement C is INCORRECT.

4. Comparing Final and Original Price
The final price of Rupees 448 is less than the original price of Rupees 500.

Statement D is correct.
2026 Prelims Maths
A gadget was sold for Rs. 522 after a 10% discount and then a 10% sales tax was applied on the discounted price. What was the original price of the gadget? (Round to nearest ten)  
A Rs. 495
B Rs. 539
C Rs. 527
D Rs. 548
Correct Answer: Option B
Assume the original price of the gadget is 100 units.

1. Applying the Discount
A 10 percent discount reduces the price by 10 units.

The discounted price becomes 90 units (100 units minus 10 units).

2. Applying the Sales Tax
A 10 percent sales tax is calculated on the discounted price of 90 units.

10 percent of 90 units is 9 units.

Adding the tax gives a final selling price of 99 units (90 units plus 9 units).

3. Finding the Original Price
The final selling price is given as Rupees 522, which corresponds to 99 units.

Dividing Rupees 522 by 99 units gives approximately Rupees 5.2727 per unit.

Multiplying 100 units by Rupees 5.2727 gives an original price of approximately Rupees 527.27.

Rounding to the nearest whole rupee gives Rupees 527.
2026 Prelims Maths
A shopkeeper marks the price of an item 40% above the cost price. He then gives two successive discounts of 10% and 5% on the marked price. If the shopkeeper makes a profit of Rs.492.5, find the cost price of the item.
A Rs.2,000
B Rs.2,100
C Rs.2,500
D Rs.2,600
Correct Answer: Option C
Assume the cost price of the item is 100 units.

1. Marked Price
The marked price is 40 percent above the cost price.

40 percent of 100 units is 40 units.

The marked price is 140 units.

2. Discounts
First discount: 10 percent on 140 units is 14 units.

Price after the first discount is 140 units minus 14 units, which equals 126 units.

Second discount: 5 percent on 126 units is 6.3 units.

The final selling price is 126 units minus 6.3 units, which equals 119.7 units.

3. Profit in Units
Profit equals selling price minus cost price.

119.7 units minus 100 units gives a profit of 19.7 units.

4. Calculate the Cost Price
The actual profit is given as Rupees 492.5.

Dividing Rupees 492.5 by 19.7 units gives Rupees 25 per unit.

Multiplying 100 units by Rupees 25 gives the cost price of Rupees 2,500.
2026 Prelims Maths
In a national competitive examination, 35% of the total candidates were girls. The results revealed the following: 75% of the boys passed the exam. 80% of the girls passed the exam. Among all the candidates who passed, 20% were awarded a merit scholarship. Among all the candidates who failed, 10% were eligible to apply for secondary "recovery" test. If the number of candidates who were awarded a scholarship exceeds the number of candidates eligible for the recovery test by 2,605, what was the total number of candidates who appeared for the exam? 
A 15,000
B 18,500
C 20,000
D 22,500
Correct Answer: Option C
The correct answer is C) 20,000.

Step-by-Step Breakdown
Assume the total number of candidates is 100 units.

1. Candidate Demographics
Girls: 35 units out of 100

Boys: 65 units out of 100

2. Passed and Failed Candidates
Passed Boys: 75 percent of 65 units is 48.75 units

Passed Girls: 80 percent of 35 units is 28 units

Total Passed: 48.75 units plus 28 units is 76.75 units

Total Failed: 100 units minus 76.75 units leaves 23.25 units

3. Scholarship and Recovery Test Candidates
Merit Scholarship: 20 percent of the 76.75 passed units is 15.35 units

Recovery Test Eligible: 10 percent of the 23.25 failed units is 2.325 units

4. Finding the Value of One Unit
Subtracting the recovery test units from the scholarship units gives 13.025 units (15.35 minus 2.325).

This difference represents 2,605 candidates.

Dividing 2,605 by 13.025 gives 200 candidates per unit.

5. Calculate Total Candidates
Multiplying 100 units by 200 candidates per unit gives 20,000 total candidates.

About JKSSB 2026 Previous Year Questions

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